如何从xml文件中删除重复的元素？

Question

我有一个XML文件

<ns0:Employees xmlns:ns0="http://TestIndexMap.Employees">
  <Employee FirstName="FirstName_0" LastName="LastName_1" dept="dept_2" empNumber="1">
    <Schedules>
      <Schedule Date_join="2008-01-20" Date_end="2008-01-30" />
    </Schedules>
  </Employee>
  <Employee FirstName="FirstName_0" LastName="LastName_1" dept="dept_2" empNumber="2">
    <Schedules>
      <Schedule Date_join="2008-01-20" Date_end="2008-01-30" />
    </Schedules>
  </Employee>
  <Employee FirstName="FirstName_2" LastName="LastName_1" dept="dept_2" empNumber="2">
    <Schedules>
      <Schedule Date_join="2007-01-21" Date_end="2007-12-30" />

    </Schedules>
  </Employee>
  <Employee FirstName="FirstName_2" LastName="LastName_1" dept="dept_2" empNumber="2">
    <Schedules>
      <Schedule Date_join="2007-01-21" Date_end="2007-12-30" />
      <Schedule Date_join="2008-06-20" Date_end="2008-01-30" />

    </Schedules>
  </Employee>
</ns0:Employees>

我想根据fistname,姓氏和date_join以及data_end删除重复项.

请问,有人可以解释如何使用XSLT实现这一目标吗？

Answer 1

以下是一些如何根据元素名称和id字段删除重复项的示例.将其扩展到任意字段应该不太难.

问:扩张.我的xml的一部分看起来像这样:

 <location>
   <state>xxxx</state>
 </location>

 <location>
    <state>yyyy</state>
 </location>

  <location>
    <state>xxxx</state>
 </location>

所需的输出是:

xxxx
yyyy

也就是说,不应打印重复的状态值.可以这样做吗？

   <xsl:variable name="unique-list"
     select="//state[not(.=following::state)]" />   

   <xsl:for-each select="$unique-list">
 <xsl:value-of select="." />
   </xsl:for-each>