我的队友为我的Android应用程序制作了数据库.例如,其中一个表是这样创建的:
CREATE TABLE table1(
id_fields_starring INTEGER PRIMARY KEY AUTOINCREMENT
, fields_descriptor_id INTEGER NOT NULL
, starring_id INTEGER NOT NULL
, form_mandatory INTEGER NOT NULL DEFAULT 1
, form_visible INTEGER NOT NULL DEFAULT 1
, FOREIGN KEY(fields_descriptor_id) REFERENCES pr_fields_descriptor(id_fields_descriptor) ON DELETE CASCADE ON UPDATE CASCADE
, FOREIGN KEY(starring_id) REFERENCES starring(id_starring) ON DELETE CASCADE ON UPDATE CASCADE
)
Run Code Online (Sandbox Code Playgroud)
从表中的字段,我需要知道其中哪些是INTEGER NOT NULL
和是INTEGER NOT NULL DEFAULT 1
,因为第一种情况下,我必须dinamically的创建EditText
和第二种情况下我必须创建一个CheckBox
.任何的想法?
Jen*_*ens 22
呼叫:
PRAGMA table_info(table1);
Run Code Online (Sandbox Code Playgroud)
将转储表信息,例如
cid|name |type |notnull |dflt_value |pk
0 |id_fields_starring |INTEGER |0 | |1
1 |fields_descriptor_id |INTEGER |1 | |0
2 |starring_id |INTEGER |1 | |0
3 |form_mandatory |INTEGER |1 |1 |0
4 |form_visible |INTEGER |1 |1 |0
Run Code Online (Sandbox Code Playgroud)
并简单地用notnull=1
和找到光标中的行dflt_value=1
要列出定义的所有列,INTEGER NOT NULL DEFAULT 1
这将是有效的(helper
是您的实例SQLiteOpenHelper
):
SQLiteDatabase db = helper.getWritableDatabase();
Cursor cursor = db.rawQuery("PRAGMA table_info(table1)", null);
try {
int nameIdx = cursor.getColumnIndexOrThrow("name");
int typeIdx = cursor.getColumnIndexOrThrow("type");
int notNullIdx = cursor.getColumnIndexOrThrow("notnull");
int dfltValueIdx = cursor.getColumnIndexOrThrow("dflt_value");
ArrayList<String> integerDefault1NotNull = new ArrayList<String>();
while (cursor.moveToNext()) {
String type = cursor.getString(typeIdx);
if ("INTEGER".equals(type)) {
// Integer column
if (cursor.getInt(notNullIdx) == 1) {
// NOT NULL
String defaultValue = cursor.getString(dfltValueIdx);
if ("1".equals(defaultValue)) {
integerDefault1NotNull.add(cursor.getString(nameIdx));
}
}
}
}
System.out.println("integerDefault1NotNull now contains a list of all columns " +
" defined as INTEGER NOT NULL DEFAULT 1, " + integerDefault1NotNull);
} finally {
cursor.close();
}
Run Code Online (Sandbox Code Playgroud)
归档时间: |
|
查看次数: |
19620 次 |
最近记录: |