如何测试Magento POST控制器操作 - 使用(或不使用)EcomDev PHPUnit模块

Question

有没有办法测试Magento POST控制器的动作？例如客户登录:

Mage_Customer_AccountController::loginPostAction()

我正在使用EcomDev_PHPUnit模块进行测试.它适用于基本操作,但我无法调用POST操作.

$this->getRequest()->setMethod('POST');
// ivokes loginAction instead loginPostAction
$this->dispatch('customer/account/login');
// fails also
$this->dispatch('customer/account/loginPost');
// but this assert pass
$this->assertEquals('POST', $_SERVER['REQUEST_METHOD']);

我想做或多或少的测试

// ... some setup
$this->getRequest()->setMethod('POST');
$this->dispatch('customer/account/login');
// since login uses singleton, then...
$session = Mage::getSingleton('customer/session');
$this->assertTrue($session->isLoggedIn());

Answer 1

在客户帐户控制器登录和loginPost是两个不同的操作.至于登录,你需要做这样的事情:

// Setting data for request
$this->getRequest()->setMethod('POST')
        ->setPost('login', array(
            'username' => 'customer@email.com',
            'password' => 'customer_password'
        ));

$this->dispatch('customer/account/loginpost'); // This will login customer via controller

但是,只有在需要测试登录过程时才需要这种测试体,但如果只想模拟客户登录,则可以创建特定客户登录的存根.我在少数项目中使用它.只需将此方法添加到测试用例中,然后在需要时使用.它将在单次测试运行中登录客户,然后将拆除所有会话更改.

/**
 * Creates information in the session,
 * that customer is logged in
 *
 * @param string $customerEmail
 * @param string $customerPassword
 * @return Mage_Customer_Model_Session|PHPUnit_Framework_MockObject_MockObject
 */
protected function createCustomerSession($customerId, $storeId = null)
{
    // Create customer session mock, for making our session singleton isolated
    $customerSessionMock = $this->getModelMock('customer/session', array('renewSession'));
    $this->replaceByMock('singleton', 'customer/session', $customerSessionMock);

    if ($storeId === null) {
        $storeId = $this->app()->getAnyStoreView()->getCode();
    }

    $this->setCurrentStore($storeId);
    $customerSessionMock->loginById($customerId);

    return $customerSessionMock;
}

还在上面的代码中模拟了renewSession方法,因为它使用的是直接的setcookie函数,而不是core/cookie模型,因此在命令行中它会产生错误.

真诚的,伊万