转到c#及其用法

Question

我有一个子程序.它可以确定值是否为空,然后执行某些操作.例如,如果它们为空,则会引发警告.代码工作正常.但是当值不为空时,警告仍然会弹出.请帮我纠正逻辑.

谢谢.

private void btnNew_Click(object sender, EventArgs e)
    {
        try
        {
            if (txtbox1.Text.ToString().Trim() == string.Empty)
            {
                goto Msg1;
            }
            if (txtbox2.Text.ToString().Trim() == string.Empty)
            {
                goto Msg2;
            }
            DataRow dr = mydataSet.Tables[0].NewRow();
            dr["Descript"] = txtbox1.Text;
            dr["Abbr"] = txtbox2.Text;
            dr["SortOrder"] = Convert.ToDecimal(numericOrder.Value);
            if (SortOrders.Contains((decimal)dr["SortOrder"]))
            {
                goto Msg3;
            }
            mydataSet.Tables[0].Rows.Add(dr);
            dgv.DataSource = mydataSet.Tables[0];
        Msg1:
            MessageBox.Show("Description is required.");
        Msg2:
            MessageBox.Show("Abbr is required.");
        Msg3:
            MessageBox.Show("Please select another one, this one is already used.");
        }
        catch (Exception ex)
        {
            MessageBox.Show(ex.Message);
        }
    }

从上面的代码中,你看到了.如果txtbox1有一些值,程序仍会显示Msg1.我想避免它.

Answer 1

因为标签只是标签,后面的代码是顺序执行的.

为什么你不能这样做:

    try
    {
        if (txtbox1.Text.ToString().Trim() == string.Empty)
        {
            MessageBox.Show("Description is required.");
            return;
        }
        if (txtbox2.Text.ToString().Trim() == string.Empty)
        {
            MessageBox.Show("Abbr is required.");
            return;
        }
        DataRow dr = mydataSet.Tables[0].NewRow();
        dr["Descript"] = txtbox1.Text;
        dr["Abbr"] = txtbox2.Text;
        dr["SortOrder"] = Convert.ToDecimal(numericOrder.Value);
        if (SortOrders.Contains((decimal)dr["SortOrder"]))
        {
            MessageBox.Show("Please select another one, this one is already used.");
            return;
        }
        mydataSet.Tables[0].Rows.Add(dr);
        dgv.DataSource = mydataSet.Tables[0];
    }
    catch (Exception ex)
    {
        MessageBox.Show(ex.Message);
    }

它更具可读性.