将Python xmlrpclib与unix域套接字一起使用？

Question

我正在尝试与之交互supervisord,我想通过unix socket(它是一个共享的托管环境)与它交谈.

到目前为止我尝试过的是:

import xmlrpclib
server = xmlrpclib.ServerProxy('unix:///path/to/supervisor.sock/RPC2')
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "/usr/local/lib/python2.7/xmlrpclib.py", line 1549, in __init__
    raise IOError, "unsupported XML-RPC protocol"
IOError: unsupported XML-RPC protocol

/path/to/supervisor.sock肯定存在.使用'unix:///path/to/supervisor.sock/RPC2'形式的URI supervisord,这是我的想法.文档不讨论unix套接字:http://docs.python.org/library/xmlrpclib.html.

这可能吗？我应该使用不同的库吗？

Answer 1

xmlrpclib要求传递的url以http或开头https.解决这个问题的方法是定义一个忽略该URL的自定义传输.以下是使用来自主管的传输的一些代码:

import supervisor.xmlrpc
import xmlrpclib

proxy = xmlrpclib.ServerProxy('http://127.0.0.1',
                               transport=supervisor.xmlrpc.SupervisorTransport(
                                    None, None, serverurl='unix://'+socketpath))

proxy.supervisor.getState()

如果这是没有用的,这里发现的代码的更新版本在这里:

class UnixStreamHTTPConnection(httplib.HTTPConnection, object):
    def __init__(self, *args, **kwargs):
        self.socketpath = kwargs.pop('socketpath')
        super(UnixStreamHTTPConnection, self).__init__(*args, **kwargs)

    def connect(self):
        self.sock = socket.socket(socket.AF_UNIX, socket.SOCK_STREAM)
        self.sock.connect_ex(self.socketpath)

class UnixStreamTransport(xmlrpclib.Transport, object):
    def __init__(self, *args, **kwargs):
        self.socketpath = kwargs.pop('socketpath')
        super(UnixStreamTransport, self).__init__(*args, **kwargs)

Answer 2

我的python3版本，从上面的版本准备。

from http.client import HTTPConnection
import socket
from xmlrpc import client

class UnixStreamHTTPConnection(HTTPConnection):
    def connect(self):
        self.sock = socket.socket(socket.AF_UNIX, socket.SOCK_STREAM)
        self.sock.connect(self.host)

class UnixStreamTransport(client.Transport, object):
    def __init__(self, socket_path):
        self.socket_path = socket_path
        super(UnixStreamTransport, self).__init__()

    def make_connection(self, host):
        return UnixStreamHTTPConnection(self.socket_path)

proxy = client.ServerProxy('http://localhost', transport=UnixStreamTransport("/var/run/supervisor.sock"))

print(proxy.supervisor.getState())

Answer 3

这是使用xmlrpclib与主管交谈的更新示例:

import httplib
import socket
import xmlrpclib

class UnixStreamHTTPConnection(httplib.HTTPConnection):
    def connect(self):
        self.sock = socket.socket(socket.AF_UNIX, socket.SOCK_STREAM)
        self.sock.connect(self.host)

class UnixStreamTransport(xmlrpclib.Transport, object):
    def __init__(self, socket_path):
        self.socket_path = socket_path
        super(UnixStreamTransport, self).__init__()

    def make_connection(self, host):
        return UnixStreamHTTPConnection(self.socket_path)


server = xmlrpclib.Server('http://arg_unused', transport=UnixStreamTransport("/var/run/supervisor.sock"))
print(server.supervisor.getState())

如前所述,我们必须使用http://或https://指定一个虚拟URL,然后指定一个自定义传输来处理域套接字