如何将id与mysql中不同表的名称相匹配？

Question

A. event_choices

event_id | res_id | 
4        | 10     | 

B. restaurants 

res_id     | res_name | 
10         | xyz      | 

C. event
event_id   | event_name | 
4          | birthday   | 

我一直在尝试使用内部联接来尝试将名称与id匹配但是不成功

select event_id as id from event_choices inner join restaurants on res_id.id = res_name

任何帮助将不胜感激,非常新的php/mysql

Answer 1

尝试:

SELECT event_id, res_name FROM event_choices, restaurants WHERE event_choices.res_id = restaurants.res_id

享受^ _ ^