如何按月拆分现有的apache日志文件？

Question

如何将现有的apache日志文件按月拆分为单独的文件？

我在网上搜索过,找不到任何东西.是的,我知道logrotate和cronolog以及所有这些.但是,我发现的任何内容都无法帮助我分割现有文件.

是否有awk脚本或其他什么？

这是一个数据片段:

124.115.5.11 - - [30/May/2011:23:21:37 -0500] "GET / HTTP/1.0" 200 206492 "-" "Mozilla/4.0 (compatible; MSIE 6.0; Windows NT 5.1; SV1; .NET CLR 1.1.4322;TencentTraveler)"
58.61.164.39 - - [31/May/2011:00:36:35 -0500] "GET / HTTP/1.0" 200 206492 "-" "Mozilla/4.0 (compatible; MSIE 6.0; Windows NT 5.1; SV1; .NET CLR 1.1.4322;TencentTraveler)"
114.80.93.55 - - [31/May/2011:01:42:17 -0500] "GET / HTTP/1.0" 200 206492 "-" "Sosospider+(+http://help.soso.com/webspider.htm)"
114.80.93.73 - - [31/May/2011:02:03:44 -0500] "GET / HTTP/1.0" 200 206492 "-" "Mozilla/4.0 (compatible; MSIE 6.0; Windows NT 5.1; SV1; .NET CLR 1.1.4322;TencentTraveler)"
123.125.71.98 - - [31/May/2011:12:33:30 -0500] "GET / HTTP/1.1" 103 24576 "-" "Baiduspider+(+http://www.baidu.com/search/spider.htm)"
220.181.108.187 - - [31/May/2011:12:33:55 -0500] "GET / HTTP/1.1" 103 24576 "-" "Baiduspider+(+http://www.baidu.com/search/spider.htm)"
123.125.71.117 - - [31/May/2011:13:27:56 -0500] "GET / HTTP/1.1" 103 24576 "-" "Baiduspider+(+http://www.baidu.com/search/spider.htm)"
123.125.71.78 - - [31/May/2011:16:45:48 -0500] "GET /node/54 HTTP/1.1" 200 3219 "-" "Mozilla/5.0 (compatible; Baiduspider/2.0; +http://www.baidu.com/search/spider.html)"
124.115.1.8 - - [31/May/2011:19:59:58 -0500] "GET / HTTP/1.1" 200 206492 "-" "Mozilla/4.0 (compatible; MSIE 6.0; Windows NT 5.1)"
123.125.71.69 - - [31/May/2011:22:05:46 -0500] "GET / HTTP/1.1" 200 206492 "-" "Mozilla/5.0 (compatible; Baiduspider/2.0; +http://www.baidu.com/search/spider.html)"

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这是我的解决方案,受到Steve的回答的极大启发:

一种方式使用awk:

awk 'BEGIN {
    split("Jan Feb Mar Apr May Jun Jul Aug Sep Oct Nov Dec ", months, " ")
    for (a = 1; a <= 12; a++)
        m[months[a]] = a
}
{
    split($4,array,"[:/]");
    year = array[3]
    month = sprintf("%02d", m[array[2]])

    print > FILENAME"-"year"_"month".txt"
}' incendiary.ws-2009

这将输出如下文件:

incendiary.ws-2010-2010_04.txt
incendiary.ws-2010-2010_05.txt
incendiary.ws-2010-2010_06.txt
incendiary.ws-2010-2010_07.txt

对于150 MB的日志文件,chepner的Accepted Answer 在3.4 GHz 8 Core Xeon E31270上花费了70秒,而这种方法耗时5秒.

原创灵感:https://stackoverflow.com/a/11714105/430062

Answer 1

一种方式使用awk:

awk '{ split($4,array,"/"); print > array[2] ".txt" }' file.txt

这将输出如下文件:

May.txt
June.txt
July.txt
etc

编辑:

也许你想把这些年份分开:

awk '{ split($4,array,"[:/]"); print > array[2] array[3] ".txt" }' file.txt

这将输出如下文件:

May2011.txt
May2012.txt
July2011.txt
etc