在mysql中只选择并显示重复的记录

Question

这个问题非常简单我出于某种原因无法获得正确的结果来显示重复的记录

Table   : Paypal_ipn_orders
id                              payer_email
1                               susan@gmail.com
2                               ryan@gmail.com   
3                               susan@gmail.com
4                               steve@gmail.com
5                               steve@gmail.com

SELECT id, COUNT( payer_email ) `tot`
FROM paypal_ipn_orders
GROUP BY payer_email
HAVING `tot` >1

样本输出

id       tot
1         2
4         2

预期产出

id       payer_email 
1        susan@gmail.com
3        susan@gmail.com
4        steve@gmail.com
5        steve@gmail.com

我该如何实现这一目标？

Answer 1

SELECT id, payer_email
FROM paypal_ipn_orders
WHERE payer_email IN (
    SELECT payer_email
    FROM paypal_ipn_orders
    GROUP BY payer_email
    HAVING COUNT(id) > 1
)

sqlfiddle

Answer 2

将IN在我的处境太慢(180秒)

所以我用了一个JOIN(0.3秒)

SELECT i.id, i.payer_email
FROM paypal_ipn_orders i
INNER JOIN (
 SELECT payer_email
    FROM paypal_ipn_orders 
    GROUP BY payer_email
    HAVING COUNT( id ) > 1
) j ON i.payer_email=j.payer_email

Answer 3

这是一个简单的例子：

select <duplicate_column_name> from <table_name> group by <duplicate_column_name> having count(*)>=2

它肯定会起作用。:)