在我有这样的事情(简化)之前,使用sbt 0.11.3:
// project/Build.scala
import sbt._
import Keys._
object MyBuild extends Build {
lazy val standardSettings = Defaults.defaultSettings ++ Seq(
version := "0.2",
scalaVersion := "2.9.2"
)
lazy val main = Project(
id = "main",
base = file( "." ),
settings = standardSettings,
aggregate = Seq( sub )
)
lazy val sub = Project(
id = "main-sub",
base = file( "sub" ),
settings = standardSettings
)
}
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但是我想在普通build.sbt文件中保留尽可能多的信息.所以现在我有
// build.sbt
version := "0.2"
scalaVersion := "2.9.2"
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和
// project/Build.scala
import sbt._
import Keys._
object MyBuild extends Build {
lazy val main = Project(
id = "main",
base = file( "." ),
aggregate = Seq( sub )
)
lazy val sub = Project(
id = "main-sub",
base = file( "sub" )
)
}
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但这似乎并没有在我的设置中混合build.sbt到子项目中:
> show version
[info] main-sub/*:version
[info] 0.1-SNAPSHOT
[info] main/*:version
[info] 0.2
> show scala-version
[info] main-sub/*:scala-version
[info] 2.9.1
[info] main/*:scala-version
[info] 2.9.2
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如何解决这个问题?我还尝试向settings子项目添加显式,例如
settings = Defaults.defaultSettingssettings = Project.defaultSettingssettings = MyBuild.settingssettings = main.settings (确定这个应该做什么?!)......但没有一个有效.
这些信息在sbt的Multi Projects文档的最后一部分中有点隐藏:
当有一个
.scala文件设置不同的项目时,很容易在不同的项目中使用重用设置.但即使使用不同的build.sbt文件,通过使用ThisBuild范围来全局应用设置,仍然可以轻松地在主构建中的所有项目之间共享设置.
从而:
// build.sbt
version in ThisBuild := "0.2"
scalaVersion in ThisBuild := "2.9.2"
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哇,如果你有二十几把钥匙,这会很糟糕.