olo*_*olm 11 android android-arrayadapter android-listview
我偶然发现了一个我无法理解的问题,所以我希望也许有人遇到同样的问题,或者知道解决问题的好方法.
我创建了一个包含ListView的视图.这个ListView包含两个TextView.问题是我不知道在哪里使用ArrayAdapter发送第二个文本视图中的值.有没有办法向ArrayAdapter发送更多信息,以便我可以提供"todaysmenu"TextView?
ArrayAdapter方法:
private void createList() {
ListView lv = (ListView) findViewById(R.id.mylist);
String[] values = new String[] { "Android", "Linux", "OSX",
"WebOS", "Windows7", "Ubuntu", "OS/2"
};
ArrayAdapter<String> adapter = new ArrayAdapter<String>(this,R.layout.rowlayout, R.id.restaurantname, values);
lv.setAdapter(adapter);
}
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行标记:
<?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:layout_width="fill_parent"
android:layout_height="wrap_content"
android:orientation="vertical" >
<TextView
android:id="@+id/restaurantname"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:text="@+id/restaurantname"
android:textSize="23dp" >
</TextView>
<TextView
android:id="@+id/textView1"
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:text="@+id/todaysmenu" />
</LinearLayout>
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活动布局:
<?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:layout_width="fill_parent"
android:layout_height="fill_parent"
android:orientation="vertical" >
<ListView
android:id="@+id/mylist"
android:layout_width="match_parent"
android:layout_height="wrap_content">
</ListView>
</LinearLayout>
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一开始我把一切都搞定了,但是当我添加第二个文本域问题时.提前谢谢你的帮助!
yug*_*oid 21
为此,您必须构建自定义适配器并为自定义行布局充气.使用ArrayAdapter将无法正常工作,因为
默认情况下,此类期望提供的资源ID引用单个TextView.如果要使用更复杂的布局,请使用也带有字段ID的构造函数.该字段id应引用较大布局资源中的TextView.
所以,你的自定义适配器类可能是这样的:
public class CustomAdapter extends ArrayAdapter {
private final Activity activity;
private final List list;
public CustomAdapter(Activity activity, ArrayList<Restaurants> list) {
this.activity = activity;
this.list = list;
}
@Override
public View getView(int position, View convertView, ViewGroup parent) {
View rowView = convertView;
ViewHolder view;
if(rowView == null)
{
// Get a new instance of the row layout view
LayoutInflater inflater = activity.getLayoutInflater();
rowView = inflater.inflate(R.layout.rowlayout, null);
// Hold the view objects in an object, that way the don't need to be "re- finded"
view = new ViewHolder();
view.retaurant_name= (TextView) rowView.findViewById(R.id.restaurantname);
view.restaurant_address= (TextView) rowView.findViewById(R.id.textView1);
rowView.setTag(view);
} else {
view = (ViewHolder) rowView.getTag();
}
/** Set data to your Views. */
Restaurants item = list.get(position);
view.retaurant_name.setText(item.getTickerSymbol());
view.restaurant_address.setText(item.getQuote().toString());
return rowView;
}
protected static class ViewHolder{
protected TextView retaurant_name;
protected TextView restaurant_address;
}
}
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你的Restaurant.java类可以像我在下面描述的那样简单:
public class Restaurants {
private String name;
private String address;
public Restaurants(String name, String address) {
this.name = name;
this.address = address;
}
public void setName(String name) {
this.name= name;
}
public String getName() {
return name;
}
public void setAddress(String address) {
this.address= address;
}
public String getAddress() {
return address;
}
}
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现在,在你的主要活动中,只需用一些数据绑定你的列表,比如;
/** Declare and initialize list of Restaurants. */
ArrayList<Restaurants> list = new ArrayList<Restaurants>();
/** Add some restaurants to the list. */
list.add(new Restaurant("name1", "address1"));
list.add(new Restaurant("name2", "address2"));
list.add(new Restaurant("name3", "address3"));
list.add(new Restaurant("name4", "address4"));
list.add(new Restaurant("name5", "address5"));
list.add(new Restaurant("name6", "address6"));
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此时,您可以将自定义适配器设置为列表
ListView lv = (ListView) findViewById(R.id.mylist);
CustomAdapter adapter = new CustomAdapter(YourMainActivityName.this, list);
lv.setAdapter(adapter);
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这就是全部,它应该工作得很好,但我强烈建议你谷歌一些更好的替代方案来实现其他适配器.
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