Django runserver in command with custom settings

Question

我尝试使用自定义设置在命令中执行runserver.但是没有加载设置:

from django.core.management.base import BaseCommand
from django.core.management import call_command
from django.core.management import setup_environ, ManagementUtility

import settings_api

setup_environ(settings_api)

class Command(BaseCommand):
    help = "Local API to retrieve realtime quotes"

    def handle(self, *args, **options):
        if not settings_api.DEBUG:
            call_command('runserver',  '127.0.0.1:8002')
        else:
            call_command('runserver',  '0.0.0.0:8002')

输出是:

Used API settings
Used API settings
Validating models...

0 errors found
Django version 1.4b1, using settings 'site.settings'
Development server is running at http://0.0.0.0:8002/
Quit the server with CONTROL-C.

Answer 1

runserver强制默认设置,除非通过--settings=.如果您想要自定义设置,请使用单独的WSGI容器(甚至是内置的容器).

Answer 2

Ignacios的回答指出了正确的方向:用自定义设置执行命令param解决了它:

./manage.py command --settings=settings_api

更多细节在这里