RegisterStartupScript不适用于ScriptManager,Updatepanel.这是为什么？

Question

protected void timer1_Tick(object sender, EventArgs e)
    {
        foreach (RepeaterItem item in rpChat.Items)
        {
            TextBox txt = item.FindControl("txtChatMessage") as TextBox;
            if (txt != null)
            {
                message[i] = txt.Text;
                i--;
            }
        }
        lblStatusChat.Text = "";
        RepeaterBind();
        string javaScript = "<script language=JavaScript>\n" + "alert('Button1_Click client-side');\n" + "</script>";

        Page.ClientScript.RegisterStartupScript(this.GetType(), "myKey", javaScript);
    }

timer_click触发和更新面板.并且警报消息不会显示在timer_tick事件上

Answer 1

当您使用更新面板时,您不能像上面那样调用javascript.你必须使用

ScriptManager.RegisterStartupScript

所以改变你的

Page.ClientScript.RegisterStartupScript(this.GetType(), "myKey", javaScript);

至

ScriptManager.RegisterStartupScript(updatePanelId,updatePanelId.GetType()
                                                      , "alert", javaScript, true);

Answer 2

您需要使用ScriptManager类,因为您在进行回发和使用updatepanel时是注册脚本

MSDN: ScriptManager.RegisterStartupScript

ScriptManager.RegisterStartupScript方法,用于在将控件包装在UpdatePanel中时将客户端脚本添加到页面.

ASPX页面

<div>
<asp:ScriptManager ID="ScriptManager1" runat="server">
</asp:ScriptManager>
<asp:UpdatePanel ID="UpdatePanel1" runat="server">
    <ContentTemplate>
        <asp:Label ID="lblDisplayDate" runat="server" Text="Label"></asp:Label>
         <asp:Button ID="btnPostback" runat="server" onclick="btnPostback_Click" 
        Text="ClickMe" />
    </ContentTemplate>
</asp:UpdatePanel>
</div>

CodeBehind注册启动脚本

protected void btnPostback_Click(object sender, EventArgs e)
{
    System.Text.StringBuilder sb = new System.Text.StringBuilder();
    sb.Append(@"<script language='javascript'>");
    sb.Append(@"var lbl = document.getElementById('lblDisplayDate');");
    sb.Append(@"lbl.style.color='red';");
    sb.Append(@"</script>");

    ScriptManager.RegisterStartupScript(btnPostback,this.GetType(), "JSCR", sb.ToString(),false);

}

详细信息:在异步回发期间使用RegisterStartupScript以编程方式添加JavaScript

Answer 3

就我而言,ScriptManager.RegisterStartupScript也不起作用.

不行:

ScriptManager.RegisterStartupScript(Me, 
  Me.GetType(), 
  String.Format("Data{0}", Me.ID), 
  "<script>alert(111);</script>", 
  False)

工作:

ScriptManager.RegisterStartupScript(Me.Page, 
  Me.GetType(), 
  String.Format("Data{0}", Me.ID), 
  "<script>alert(111);</script>", 
  False)

Me 在示例中是继承自我的自定义控件 System.Web.UI.WebControls.WebParts.WebPart