将变量分配给{%include%}标记Django中的子模板

Question

我有这个代码(它没有给我预期的结果)

#subject_content.html
{% block main-menu %}
    {% include "subject_base.html" %}
{% endblock %}


#subject_base.html
....
....
    <div id="homework" class="tab-section">
        <h2>Homework</h2>
            {% include "subject_file_upload.html" %}
    </div>

儿童模板:

#subject_file_upload.html
    <form action="." method="post" enctype="multipart/form-data">{% csrf_token %}
        {{ form.as_p }}
        <input type="submit" value="submit">
    </form>

和我的看法

#views.py
@login_required
def subject(request,username, subject):
    if request.method == "POST":
        form = CarsForm(request.POST, request.FILES)
        if form.is_valid():
            form.save()
            return HttpResponseRedirect("/")
    form = CarsForm()
    return render_to_response('subject_content.html', {'form':form}, context_instance=RequestContext(request))

上面的代码以我希望的方式创建HTML,但是表单不会更新数据库.

但,

如果我跳过中间模板并直接转到上传表单,它可以正常工作:

#subject_content.html
{% block main-menu %}
    {% include "subject_file_upload.html" %}
{% endblock %}

请帮助我使用中间模板.我想这样做,因为我不想多次输入相同的代码.

Answer 1

就像@Besnik建议的那样,它非常简单:

{% include "subject_file_upload.html" with form=form foo=bar %}

在对文件include提到了这一点.它还提到您可以使用only仅使用给定变量呈现模板,而不继承任何其他变量.

谢谢@Besnik