通过OutputDataReceived事件捕获进程输出

Question

我正试图以"实时"(当它正在运行时)捕获过程输出.我使用的代码相当简单(见下文).由于某些奇怪的原因,从不调用OutputDataReceived事件.为什么？

private void button2_Click(object sender, EventArgs e)
    {
      // Setup the process start info
      var processStartInfo = new ProcessStartInfo("ping.exe", "-t -n 3 192.168.100.1")
      {
        UseShellExecute = false,
        RedirectStandardOutput = true
      };

      // Setup the process
      mProcess = new Process { StartInfo = processStartInfo, EnableRaisingEvents = true };

      // Register event
      mProcess.OutputDataReceived += OnOutputDataReceived;

      // Start process
      mProcess.Start();
      mProcess.WaitForExit();
    }

    void OnOutputDataReceived(object sender, DataReceivedEventArgs e)
    {
       //Never gets called...
    }

Answer 1

你需要打电话

mProcess.BeginOutputReadLine();

BeginOutputReadLine - "在应用程序的重定向StandardOutput流上开始异步读取操作."