use*_*085 1 c# sql-server transactions transactionscope
我第一次玩交易我以为我会得到以下代码:
namespace database
{
class Program
{
static string connString = "Server=ServerName;Database=Demo;Trusted_Connection=True;";
SqlConnection connection = new SqlConnection(connString);
static Random r = new Random();
static void Add()
{
try
{
Thread.Sleep(r.Next(0, 10));
using (var trans = new TransactionScope())
{
using (var conn = new SqlConnection(connString))
{
conn.Open();
var count = (int)new SqlCommand("select balance from bank WITH (UPDLOCK) where owner like '%Jan%'", conn).ExecuteScalar();
Thread.Sleep(r.Next(0, 10));
SqlCommand cmd = new SqlCommand("update bank set balance = " + ++count + "where owner like '%Jan%'", conn);
cmd.ExecuteNonQuery();
}
trans.Complete();
}
}
catch (Exception ex)
{
Console.WriteLine(ex.Message);
}
}
static void Remove()
{
try
{
Thread.Sleep(r.Next(0, 10));
using (var trans = new TransactionScope())
{
using (var conn = new SqlConnection(connString))
{
conn.Open();
var count = (int)new SqlCommand("select balance from bank WITH (UPDLOCK) where owner like '%Jan%'", conn).ExecuteScalar();
Thread.Sleep(r.Next(0, 10));
SqlCommand cmd = new SqlCommand("update bank set balance = " + --count + "where owner like '%Jan%'", conn);
cmd.ExecuteNonQuery();
}
trans.Complete();
}
}
catch (Exception ex)
{
Console.WriteLine(ex.Message);
}
}
static void Main(string[] args)
{
for (int i = 0; i < 5; i++)
{
Thread t = new Thread(new ThreadStart(Add));
t.Start();
}
for (int i = 0; i < 5; i++)
{
Thread t = new Thread(new ThreadStart(Remove));
t.Start();
}
Console.ReadLine();
}
}
}
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我假设最后在100次加法和100次减法之后,我的balane将与我的起点相同 - 100,但是每次我运行脚本时它都会不断变化.即使使用isolationlevel可序列化.谁能告诉我为什么?O_O
编辑:将连接打开和关闭移动到事务范围内.现在的问题是我得到"事务(进程ID XX)与另一个进程锁定资源上的死锁,并被选为死锁牺牲品.重新运行事务"
像Marc Gravell Said一样:将连接放在事务范围内并将UPDLOCK添加到select查询并结合更改isolationlevel到repeatableRead就可以了:)
static void Add()
{
try
{
Thread.Sleep(r.Next(0, 10));
using (var trans = new TransactionScope(TransactionScopeOption.Required, new TransactionOptions() { IsolationLevel = IsolationLevel.RepeatableRead }))
{
using (var conn = new SqlConnection(connString))
{
conn.Open();
var count = (int)new SqlCommand("select balance from bank WITH (UPDLOCK) where owner like '%Jan%'", conn).ExecuteScalar();
Thread.Sleep(r.Next(0, 10));
SqlCommand cmd = new SqlCommand("update bank set balance = " + ++count + "where owner like '%Jan%'", conn);
cmd.ExecuteNonQuery();
}
trans.Complete();
}
}
catch (Exception ex)
{
Console.WriteLine(ex.Message);
}
}
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1:目前TransactionScope可能是多余的和未使用的; 尝试更改事务以包装连接,而不是相反(哦,并使用using):
using (var trans = new TransactionScope(TransactionScopeOption.Required,
new TransactionOptions() { IsolationLevel = IsolationLevel.Serializable }))
using (var conn = new SqlConnection(connString))
{
conn.Open();
//...
trans.Complete();
}
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这样,连接应该在事务中正确登记(并且如果发生了不好的事情,可以正确清理)
我认为以上是主要问题 ; 即没有参与交易.这意味着可能会丢失更改,因为读/写操作实际上并未提升到更高的隔离级别.
2:但是,如果你自己这样做,我希望你会看到死锁.为了避免死锁,如果你知道你要更新,你可能想要使用(UPDLOCK)它select- 这将在开始时采用写锁定,这样如果有一个竞争线程,你得到一个块而不是死锁.
要清楚,这种死锁情况是由以下原因引起的:
添加UPDLOCK,这变为:
3:但查询做一个微不足道的更新是愚蠢的; 更好的方法是在不选择的情况下发布就地更新,即update bank set balance = balance + 1 where ...
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