在下面的代码中,CheckBox没有出现在Table的第一行.任何人都可以帮帮我..
rgds,Sirojan
<body>
<form method="post" action="<?php echo $_SERVER['PHP_SELF'];?>"
<?php
$dbc=mysqli_connect("localhost","root","","elvis_store") or die("Error Connecting to Mysql Database");
$query="SELECT * FROM email_list";
$result=mysqli_query($dbc,$query)or die("Query Syntaxt is Incorrect");
while($row=mysqli_fetch_array($result)){
echo '<input type="checkbox" value="'.$row['id'].'" name="todelete[]"/>';
echo $row['first_name']." ".$row['last_name']." ".$row['email'];
echo "<br/>";
}
mysqli_close($dbc);
?>
<input type="submit" name"submit" value="Remove"/>
</body>
您的form代码未在第一行关闭
<form method="post" action="<?php echo $_SERVER['PHP_SELF'];?>"
它应该是
<form method="post" action="<?php echo $_SERVER['PHP_SELF'];?>">