Ani*_*oel 2 c# windows httpwebrequest httpwebresponse
有许多站点在表单提交时调用脚本并使用HTTP POST或GET传递参数,使用Web调试器我已经找到了传递的参数.现在我希望通过我在C#中的Windows应用程序做同样的事情.我怎样才能实现这样的功能?
我目前在C#中使用HttpWebRequest和HttpWebResponse类.但这是一个痛苦,因为我必须为我尝试加载和工作的每个页面编写显式代码.例如,我正在尝试将用户名和密码传递到php页面并获取响应,该响应将发送cookie和页面作为回报,基于此我确定用户是否已登录.
HttpWebRequest loginreq = createreq("http://www.indyarocks.com/mobile/index.php");
String logintext = "username=" + TxtUsrname.Text + "&pass=" + TxtPasswd.Password + "&button.x=0&button.y=0";
loginreq.ContentLength = logintext.Length;
StreamWriter writerequest = new StreamWriter(loginreq.GetRequestStream());
writerequest.Write(logintext);
writerequest.Close();
HttpWebResponse getloginpageresponse = (HttpWebResponse)loginreq.GetResponse();
cookie = getloginpageresponse.Cookies[0];
BinaryFormatter bf1 = new BinaryFormatter();
Stream f1 = new FileStream("E:\\cookie.dat", FileMode.OpenOrCreate);
bf1.Serialize(f1, cookie);
f1.Close();
string nexturl = getloginpageresponse.Headers[HttpResponseHeader.Location];
StreamReader readresponse = new StreamReader(getloginpageresponse.GetResponseStream());
if (nexturl == "p_mprofile.php")
{
MessageBox.Show("Login Successful");
GrpMsg.IsEnabled = true;
}
else if (nexturl == "index.php?msg=1")
{
MessageBox.Show("Invalid Credentials Login again");
}
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这是我的createreq类
private HttpWebRequest createreq(string url)
{
HttpWebRequest temp = (HttpWebRequest)WebRequest.Create(url);
temp.Method = "POST";
temp.UserAgent = "Mozilla/4.0 (compatible; MSIE 7.0; Windows NT 6.0; SLCC1; .NET CLR 2.0.50727; Media Center PC 5.0; .NET CLR 3.0.04506; .NET CLR 3.5.21022; FDM)";
temp.KeepAlive = true;
temp.ContentType = "application/x-www-form-urlencoded";
temp.CookieContainer = new CookieContainer();
temp.AllowAutoRedirect = false;
return temp;
}
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我在正确的轨道上吗?有没有更好的方法呢?
您可以使用它来使用您想要的任何方法和标题发出请求,并通过简单的流读取获得结果页面.
在MSDN页面上有一个简单的示例,但是使用它的一些示例代码可能如下所示:
WebClient webclient= new WebClient();
using (StreamReader reader = new StreamReader(webclient.OpenRead("http://www.google.com")))
{
string result = reader.ReadToEnd();
// Parse web page here
}
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