为什么JSHint反对按位运算符？我该如何表达这段代码？

Question

我正在使用这段JavaScript生成一个UID:

(原版的:)

//If ID has not been defined then generate a new unique ID.
if(!id){
    id = 'xxxxxxxx-xxxx-4xxx-yxxx-xxxxxxxxxxxx'.replace(/[xy]/g, function (c) { var r = Math.random() * 16 | 0, v = c == 'x' ? r : (r & 0x3 | 0x8); return v.toString(16); });
}

(格式化,以便可以阅读:)

// If ID has not been defined then generate a new unique ID.
if (!id) {
    id = 'xxxxxxxx-xxxx-4xxx-yxxx-xxxxxxxxxxxx'.replace(
        /[xy]/g, 
        function (c) { 
            var r = Math.random() * 16 | 0, 
                v = c == 'x' ? r : (r & 0x3 | 0x8); 
            return v.toString(16); 
        }
    );
}

JSHint不喜欢使用按位OR和AND运算符.我想知道如何重写这个更"标准友好".

编辑:JSHint声明:

Line 8: id = 'xxxxxxxx-xxxx-4xxx-yxxx-xxxxxxxxxxxx'.replace(/[xy]/g, function (c) { var r = Math.random() * 16 | 0, v = c == 'x' ? r : (r & 0x3 | 0x8); return v.toString(16); });
Unexpected use of '|'.

Line 8: id = 'xxxxxxxx-xxxx-4xxx-yxxx-xxxxxxxxxxxx'.replace(/[xy]/g, function (c) { var r = Math.random() * 16 | 0, v = c == 'x' ? r : (r & 0x3 | 0x8); return v.toString(16); });
Expected '===' and instead saw '=='.

Line 8: id = 'xxxxxxxx-xxxx-4xxx-yxxx-xxxxxxxxxxxx'.replace(/[xy]/g, function (c) { var r = Math.random() * 16 | 0, v = c == 'x' ? r : (r & 0x3 | 0x8); return v.toString(16); });
Unexpected use of '&'.

Line 8: id = 'xxxxxxxx-xxxx-4xxx-yxxx-xxxxxxxxxxxx'.replace(/[xy]/g, function (c) { var r = Math.random() * 16 | 0, v = c == 'x' ? r : (r & 0x3 | 0x8); return v.toString(16); });
Unexpected use of '|'.

Answer 1

放

/*jshint bitwise: false*/

在文件的顶部

可用选项列表:http://jshint.com/docs/options/

Answer 2

根据JSHint的文档,这是因为

"在JavaScript程序中,按位运算符非常罕见"

正如其他人所提到的,您可以禁用bitwiseJSHint选项来压制警告.

Answer 3

你把这么多代码塞进了一行(为什么？),你无法分辨出jshint指向你的是什么.我重新格式化了代码,我看到了这个:

var r = Math.random() * 16 | 0, 

在那| 0做什么？这是一个不必要的无操作.更新:似乎是一种int-ify浮点数的方法.

Jshint似乎不喜欢其他东西,但至少要摆脱这个.并传播您的代码,以便您(和其他人)可以阅读它.