我有代码要求用户输入日志文件名,以便它知道要解析和排序的文件.
为了能够正确解析,FileSource.parseXML读取变量类型File.因此,输入String需要转换为File.怎么做?
import java.io.*;
import java.util.*;
public class Main
{
public static void main( String[] args )
{
FileSource src;
File fd=null;
int rc = 0;
int count = 0;
Record rec;
//ask user what file to parse
Scanner input = new Scanner(System.in);
System.out.println("Enter file name:");
String filename = input.nextLine();
//TODO turn filename into fd
//parse the records
src = FileSource.parseXML( fd );
//print out the number of records parsed
rc = src.getRecordCount();
System.out.println(rc);
//print out all records.
for( int i = 0; i < rc; i++)
{
rec = src.getRecord( i );
System.out.println( rec.toString());
} //end for loop
return;
}//end main method
}
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jra*_*rad 34
File file = new File(userInput);
看到你有文件名,你应该能够创建一个文件:
File file = new File(filename);
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有关文件的更多信息,请参阅此 javadoc 。