art*_*lay 18 ajax jquery callback
我已经回顾了很多这类问题的答案,现在我对最好的方法感到困惑.考虑到最新的jquery,我想要
在调用函数(doAjax)中,如何等待回调然后完成成功或错误的处理(在这种情况下,它成功清除表单,出错时保持原样)
感谢任何建议,
艺术 [编辑] 你们发现有一个错字,打电话应该是doAnAjax不做阿贾克斯
$(function () {
doAnAjax(Url, data, function (myRtn) {
if (myRtn == "success") {
resetForm($('#myForm'));
resetForm($('form[name=addChlGrp]'));
} else {
$('.rtnMsg').html("Opps! Ajax Error");
}
});
});
function doAnAjax(newUrl, data) {
$.ajax({
url: newUrl,
async: true,
dataType: 'html',
beforeSend: function () {
$('.rtnMsg').html("<img src=_cssStyleImg_-A-loading.gif>");
},
type: "GET",
data: data,
cache: false,
success: function (data, textStatus, xhr) {
$('.rtnMsg').html(data);
myRtnA = "Success"
return myRtnA;
},
error: function (xhr, textStatus, errorThrown) {
$('.rtnMsg').html("opps: " + textStatus + " : " + errorThrown);
myRtnA = "Error"
return myRtnA;
}
});
}
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the*_*dox 18
你必须使用回调函数.试试这个:
$(function() {
// I think doAjax should doAnAjax()
// here you're passing callback
// but you're not using it doAnAjax()
doAnAjax(Url, data, function(myRtn) {
if (myRtnV == "success") {
resetForm($('#myForm'));
resetForm($('form[name=addChlGrp]'));
} else {
$('.rtnMsg').html("Opps! Ajax Error");
}
});
});
// pass callback as third parameter to doAnAjax()
function doAnAjax(newUrl, data, callBack) {
$.ajax({
url: newUrl,
async: true,
dataType: 'html',
beforeSend: function() {
$('.rtnMsg').html("<img src=_cssStyleImg_-A-loading.gif>");
},
type: "GET",
data: data,
cache: false,
success: function(data, textStatus, xhr) {
$('.rtnMsg').html(data);
myRtnA = "Success"
return callBack( myRtnA ); // return callBack() with myRtna
},
error: function(xhr, textStatus, errorThrown) {
$('.rtnMsg').html("opps: " + textStatus + " : " + errorThrown);
myRtnA = "Error"
return callBack ( myRtnA ); // return callBack() with myRtna
}
});
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