如何从iphone中的sqlite Data BAse获取NSInteger值

Question

如何从iPhone SQLite数据库获取整数值通常我们使用以下是varchar或string但是我们如何获得NSInteger值？

    const char *sql = "select * from questions";
    sqlite3_stmt *selectstmt;
    if(sqlite3_prepare_v2(database, sql, -1, &selectstmt, NULL) == SQLITE_OK) {

        while(sqlite3_step(selectstmt) == SQLITE_ROW) {

            NSInteger primaryKey = sqlite3_column_int(selectstmt, 0);
            DataController *coffeeObj = [[DataController alloc] initWithPrimaryKey:primaryKey];

            coffeeObj.restaurantLocation = [NSString stringWithUTF8String:(char *)sqlite3_column_text(selectstmt, 1)];

            coffeeObj.foodQualityRating = [NSString stringWithUTF8String:(char *)sqlite3_column_text(selectstmt, 2)];

restaurantlocation和foodquality rating或NSString我在Integer中有调查ID我们如何从表中获取它.

Answer 1

如果surveyId字段是食品质量后表格中的下一列,您将使用以下代码:

coffeeObj.surveyId = sqlite3_column_int(selectstmt, 3);

语句结尾处的3是列索引