将数据从HTML表单发送到Flask中的Python脚本

Question

我的Python脚本中有以下代码:

def cmd_wui(argv, path_to_tx):
    """Run a web UI."""
    from flask import Flask, flash, jsonify, render_template, request
    import webbrowser
    app = Flask(__name__)


    @app.route('/tx/index/')
    def index():
        """Load start page where you select your project folder
        or load history projects from local DB."""
        from txclib import get_version
        txc_version = get_version()
        prj = project.Project(path_to_tx)

        # Let's create a resource list from our config file
        res_list = []
        prev_proj = ''
        for idx, res in enumerate(prj.get_resource_list()):
                hostname = prj.get_resource_host(res)
        username, password = prj.getset_host_credentials(hostname)
        return render_template('init.html', txc_version=txc_version, username=username)

另外,我在init.html中有一个HTML表单:

<form>
<input type="text" id="projectFilepath" size="40" placeholder="Spot your project files">
<input type="button" id="spotButton" value="Spot">
</form>

当用户在我的python脚本中的变量上单击"spotButton"时,如何从"projectFilepath"传递用户输入？

我是Python和Flask的新手,如果我犯了任何错误,请原谅我.

Answer 1

该form标记需要两个属性进行设置:

1. action:表单数据在提交时发送到的URL.用它生成它url_for.如果相同的URL处理显示表单并处理数据,则可以省略它.
2. method:是否将数据作为查询字符串(GET)或表单数据(POST)提交.

添加视图以处理表单数据:

@app.route('/handle_data', methods=['POST'])
def handle_data():
    projectpath = request.form['projectFilepath']
    # your code
    # return a response

将表单设置input为该视图的URL:

<form action="{{ url_for('handle_data') }}" method="post">
    <input type="text" name="projectFilepath">
    <input type="submit">
</form>

Answer 2

您需要一个将接收POST数据的Flask视图和一个将发送它的HTML表单.

from flask import request

@app.route('/addRegion', methods=['POST'])
def addRegion():
    ...
    return (request.form['projectFilePath'])

<form action="{{ url_for('addRegion') }}" method="post">
    Project file path: <input type="text" name="projectFilePath"><br>
    <input type="submit" value="Submit">
</form>