动态地以干燥的方式在Grails中构建createCriteria?

Wee*_*zle 6 grails groovy createcriteria

我正在努力建立一个createCriteria动态的.到现在为止还挺好:

obj是我想要的域对象

rulesList是一个地图列表,其中包含要搜索的字段,要使用的运算符以及要搜索的值

def c = obj.createCriteria()
l = c.list (max: irows, offset: offset) {
    switch(obj){           //constrain results to those relevant to the user
        case Vehicle:
            eq("garage", usersGarage)
            break
        case Garage:
            users {
                idEq(user.id)
            }
            break
    }
    rulesList.each { rule ->
        switch(rule['op']){
            case 'eq':
                eq("${rule['field']}", rule['value'])
                break
            case 'ne':
                ne("${rule['field']}", rule['value'])
                break
            case 'gt':
                gt("${rule['field']}", rule['value'])
                break;
            case 'ge':
                ge("${rule['field']}", rule['value'])
                break
            case 'lt':
                lt("${rule['field']}", rule['value'])
                break
            case 'le':
                le("${rule['field']}", rule['value'])
                break
            case 'bw':
                ilike("${rule['field']}", "${rule['value']}%")
                break
            case 'bn':
                not{ilike("${rule['field']}", "${rule['value']}%")}
                break
            case 'ew':
                ilike("${rule['field']}", "%${rule['value']}")
                break
            case 'en':
                not{ilike("${rule['field']}", "%${rule['value']}")}
                break
            case 'cn':
                ilike("${rule['field']}", "%${rule['value']}%")
                break
            case 'nc':
                not{ilike("${rule['field']}", "%${rule['value']}%")}
                break
            }
        }
    }
}
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上面的代码工作正常,只是看起来有点冗长的switch语句.但是,如果我想添加选择匹配任何规则或所有规则的功能,该怎么办?我需要有条件地将规则放在一个or{}.我做不了类似的事情

if(groupOp == 'or'){
    or{
}
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在我通过rulesList然后

if(groupOp == 'or'){
    }
}
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之后.我能想到的就是为每个条件重复代码:

if(groupOp == 'or'){
    or{
        rulesList.each { rule ->
            switch(rule['op']){
                ...
            }
        }
    }
}
else{
    rulesList.each { rule ->
        switch(rule['op']){
            ...
        }
    }
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现在代码看起来很草率和重复.假设我想搜索域对象属性的属性?(例如:我想要归还轮胎属于特定品牌的车辆; vehicle.tires.brand,或者司机与名称匹配的车辆; vehicle.driver.name).我是否必须做以下事情:

switch(rule['op']){
    case 'eq':
        switch(thePropertiesProperty){
            case Garage:
                garage{
                    eq("${rule['field']}", rule['value'])
                }
                break
            case Driver:
                driver{
                     eq("${rule['field']}", rule['value'])
                }
                break
        }
        break
    case 'ne':
        ...
}
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Ian*_*rts 9

首先,您可以使用GString作为方法名称来简化您的大开关:

case ~/^(?:eq|ne|gt|ge|lt|le)$/:
  "${rule['op']}"("${rule['field']}", rule['value'])
  break
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同样的技巧适用于和/或:

"${(groupOp == 'or') ? 'or' : 'and'}"() {
  rulesList.each { rule ->
    switch(rule['op']){
        ...
    }
  }
}
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或者您可以先将闭包赋值给变量,然后调用or(theClosure)and(theClosure)适当调用.最后,对于"属性"搜索,如果添加

createAlias('driver', 'drv')
createAlias('garage', 'grg')
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在条件闭包的顶部,您可以查询诸如eq('drv.name', 'Fred')无需添加干预driver {...}garage {...}节点之类的事情.