当我使用jQuery AJAX在我的页面上提交tinyMCE表单时,实际提交到数据库需要两次点击

Question

我已经尝试了一个多星期的不同选择,似乎没有任何效果.更复杂的是,我在页面上有多个表单,所有表单都需要绑定到同一个提交函数.它们都有不同的ID.

以下是我的jQuery的简化版本:

$('form').on('submit', function(form){
    var data = $(this).serialize();
    $.ajax({
        type:       'POST',
        cache:      false,
        url:        'inc/process.php',
        data:       data,
        success:    function(){
                        // The following fires on first AND second submit
                        console.log("Updates have successfully been ajaxed");
        }
    });
    return false;
});

我也试过使用$('form').submit()相同的结果.

process.php的相关部分:

$query =    'UPDATE     pop_contents
            SET     ';
$id = $_POST['content_id'];
/* to avoid including in MySQL query later */
unset($_POST['content_id']);

$length = count($_POST);
$count = 0;
foreach($_POST as $col => $value){
    $value = trim($value);
    $query .= $col."='".escapeString($value);
    // don't add comma after last value to update
    if(++$count != $length){ $query .= "', "; }
    // add space before WHERE clause
    else{ $query .= "'  "; }
}
$query .= 'WHERE        id='.$id;

$update_result = $mysqli->query($query);

Answer 1

经过多次拔毛和咒骂后,我解决了这个问题.

TinyMCE编辑器实例不直接编辑textareas,因此为了提交表单,我需要tinyMCE.triggerSave()先从TinyMCE API调用.所以,工作代码如下所示:

$('form').on('submit', function(form){
    // save TinyMCE instances before serialize
    tinyMCE.triggerSave();

    var data = $(this).serialize();
    $.ajax({
        type:       'POST',
        cache:      false,
        url:        'inc/process.php',
        data:       data,
        success:    function(){
                        console.log("Updates have successfully been ajaxed");
        }
    });
    return false;
});