Kri*_*eni 26 validation android android-edittext onclicklistener
我有验证editText.如果该editText字段为空,则应验证失败并停止用户移动到另一个Activity,因为需要值.怎么做?我知道这是一个基本问题,但我无法弄清楚如何做到这一点.
我的代码:
btninsert = (Button)findViewById(R.id.btn_insert);
btninsert.setOnClickListener( new View.OnClickListener() {
public void onClick(View v) {
insertValues();
EditText userName = (EditText) findViewById(R.id.editText1);
if( userName.getText().toString().length() == 0 )
userName.setError( "First name is required!" );
Intent i = new Intent(getApplicationContext(), Login.class);
startActivity(i);
}
});
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Button 单击此按钮时,用户将重定向到下一个屏幕,但是如果验证失败,我需要保持当前状态Activity,并且只有在验证成功时(即已输入值),他们才会转到下一个屏幕Activity.
Har*_*ary 65
这很容易...检查您的EditText是否为空,如下面的示例所示.
if( TextUtils.isEmpty(userName.getText())){
/**
* You can Toast a message here that the Username is Empty
**/
userName.setError( "First name is required!" );
}else{
Intent i = new Intent(getApplicationContext(), Login.class);
startActivity(i);
}
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试试这个:
bt.setOnClickListener(new OnClickListener() {
public void onClick(View arg0)
{
String str=et.getText().toString();
if(str.equalsIgnoreCase(""))
{
et.setHint("please enter username");//it gives user to hint
et.setError("please enter username");//it gives user to info message //use any one //
}
else
{
Intent in=new Intent(getApplicationContext(),second.class);
startActivity(in);
}
}
});
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你也可以试试这个:
if ( ( userName.getText().toString().trim().equals("")) )
{
Toast.makeText(getApplicationContext(), "User name is empty", Toast.LENGTH_SHORT).show();
}
else
{
Intent i = new Intent(getApplicationContext(), Login.class);
startActivity(i);
}
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