在字符串中用一个字符替换另一个字符

Question

我有如下数据:

A:B:C:D

我想替换Cwith数据(比方说Z),以便它看起来像

A:B:Z:D

我该怎么做？

Answer 1

=SUBSTITUTE(A1,"C","Z")

虽然我不清楚你是否想要,G或者Z你提到G但是你的示例输出显示了Z.

Answer 2

如果单元格 A1 中有 A:B:C:D，则以下方法有效：

=CONCATENATE(MID(A1, 1, SEARCH(":", MID(A1, SEARCH(":", A1) + 1, LEN(A1) - SEARCH(":", A1) + 1)) + SEARCH(":", A1)), "Z", MID(MID(MID(A1, SEARCH(":", A1) + 1, LEN(A1) - SEARCH(":", A1) + 1), SEARCH(":", MID(A1, SEARCH(":", A1) + 1, LEN(A1) - SEARCH(":", A1) + 1)) + 1, LEN(MID(A1, SEARCH(":", A1) + 1, LEN(A1) - SEARCH(":", A1) + 1)) - SEARCH(":", MID(A1, SEARCH(":", A1) + 1, LEN(A1) - SEARCH(":", A1) + 1)) + 1), SEARCH(":", MID(MID(A1, SEARCH(":", A1) + 1, LEN(A1) - SEARCH(":", A1) + 1), SEARCH(":", MID(A1, SEARCH(":", A1) + 1, LEN(A1) - SEARCH(":", A1) + 1)) + 1, LEN(MID(A1, SEARCH(":", A1) + 1, LEN(A1) - SEARCH(":", A1) + 1)) - SEARCH(":", MID(A1, SEARCH(":", A1) + 1, LEN(A1) - SEARCH(":", A1) + 1)) + 1)), LEN(MID(MID(A1, SEARCH(":", A1) + 1, LEN(A1) - SEARCH(":", A1) + 1), SEARCH(":", MID(A1, SEARCH(":", A1) + 1, LEN(A1) - SEARCH(":", A1) + 1)) + 1, LEN(MID(A1, SEARCH(":", A1) + 1, LEN(A1) - SEARCH(":", A1) + 1)) - SEARCH(":", MID(A1, SEARCH(":", A1) + 1, LEN(A1) - SEARCH(":", A1) + 1)) + 1))))

我知道这非常复杂，但它确实有效。

编辑：要清楚的是，您可以将“Z”替换为要添加的数据。