无法在Java/Groovy中创建zip文件

Question

我已尝试过多种方法在Java/Groovy中创建此zip文件.我尝试的前几种方法,来自各种博客/帖子,导致无法打开的损坏的zip文件.所以,我试过这个(下面)看起来相当有前途.sysouts报告传递给FileInputStream的有效文件路径.我不确定是否是传递给ZipOutputStream的FQ路径导致了问题.无论哪种方式,下面是代码,这导致创建小(188kb)zip文件(没有条目).有什么建议？

import java.io.FileInputStream;
import java.io.FileNotFoundException;
import java.io.FileOutputStream;
import java.io.IOException;
import java.util.Set;
import java.util.zip.ZipEntry;
import java.util.zip.ZipOutputStream;

class FileZipper {

    public static void makeZip(Set fullyQualifiedFileNames, String zipFileName, String outDir) throws IOException, FileNotFoundException
    {
        // These are the files to include in the ZIP file
        Object[] filenames = fullyQualifiedFileNames.toArray();
        String fileSeparator =  (String) System.getProperties().get("file.separator");

        // Create a buffer for reading the files
        byte[] buf = new byte[1024];

        // Create the ZIP file
        String outFilename = outDir + fileSeparator +zipFileName;
        FileOutputStream fos = new FileOutputStream(outFilename);
        ZipOutputStream zos = new ZipOutputStream(fos);
        System.out.println("Zipping to file " +outFilename);
        // Compress the files

        for (Object fileName: filenames)
        {
            System.out.println("Adding file: " + fileName);
            FileInputStream fis = new FileInputStream((String)fileName);

            // Add ZIP entry to output stream.
            String[] nodes = ((String)fileName).split("[/[\\\\]]");
            String zipEntry = nodes[nodes.length-1];
            System.out.println("Adding Zip Entry: " + zipEntry);
            zos.putNextEntry(new ZipEntry((String)fileName));

            // Transfer bytes from the file to the ZIP file
            int len;
            int totalBytes = 0;
            while ((len = fis.read(buf)) > 0) 
            {
                totalBytes += len;
                zos.write(buf, 0, len);
            }
            System.out.println("Zipped " +totalBytes +" bytes");
            // Complete the entry
            zos.closeEntry();
            fis.close();
        }

        // Complete the ZIP file
        zos.close();
        fos.close();
    }
}

Answer 1

如果您使用的是Groovy,最简单的方法是使用AntBuilder:

new AntBuilder().zip(
   destfile: "myfile.zip",
   basedir: "baseDir")

或者从Groovy 1.8开始:

ant.zip(destfile: 'file.zip', basedir: 'src_dir')