我有2个词:
dicts1 = {'field1':'', 'field2':1, 'field3':1.2}
dicts2 = {'field1':123, 'field2':123, 'field3':'123'}
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我想将每个值转换dict2为与相应值相同的类型dict1,这是最快的pythonic方式吗?
Jon*_*nts 22
假设它们是兼容的类型:
for k, v in dicts1.iteritems():
try:
dicts2[k] = type(v)(dicts2[k])
except (TypeError, ValueError) as e:
pass # types not compatible
except KeyError as e:
pass # No matching key in dict
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