在android中合并两个或多个.wav文件

Har*_*rsh 9 android

首先,我必须告诉你,我是android的新手.我想组合两个.wav(音频文件)文件.我已经开始搜索它,使用javax包很容易将它们组合在一起但是在android上不支持它.你能告诉我如何在android中做到这一点.你能建议我任何可以提供帮助的教程或图书馆吗?Thanx提前

Vip*_*hah 12

作为新手,用户只需从文件中读取字节并将其与第二个文件连接起来!

但它不会那样工作.你在组合两个文件时必须非常小心波文件头.但是我已经准备好了与我一起帮助你的代码片段.

干得好

private void CombineWaveFile(String file1, String file2) {
    FileInputStream in1 = null, in2 = null;
    FileOutputStream out = null;
    long totalAudioLen = 0;
    long totalDataLen = totalAudioLen + 36;
    long longSampleRate = RECORDER_SAMPLERATE;
    int channels = 2;
    long byteRate = RECORDER_BPP * RECORDER_SAMPLERATE * channels / 8;

    byte[] data = new byte[bufferSize];

    try {
        in1 = new FileInputStream(file1);
        in2 = new FileInputStream(file2);

        out = new FileOutputStream(getFilename3());

        totalAudioLen = in1.getChannel().size() + in2.getChannel().size();
        totalDataLen = totalAudioLen + 36;

        WriteWaveFileHeader(out, totalAudioLen, totalDataLen,
        longSampleRate, channels, byteRate);

        while (in1.read(data) != -1) {

            out.write(data);

        }
        while (in2.read(data) != -1) {

            out.write(data);
        }

        out.close();
        in1.close();
        in2.close();

        Toast.makeText(this, "Done!!", Toast.LENGTH_LONG).show();
    } catch (FileNotFoundException e) {
        e.printStackTrace();
    } catch (IOException e) {
        e.printStackTrace();
    }
}

private void WriteWaveFileHeader(FileOutputStream out, long totalAudioLen,
long totalDataLen, long longSampleRate, int channels, long byteRate)
throws IOException {

    byte[] header = new byte[44];

    header[0] = 'R';
    header[1] = 'I';
    header[2] = 'F';
    header[3] = 'F';
    header[4] = (byte)(totalDataLen & 0xff);
    header[5] = (byte)((totalDataLen >> 8) & 0xff);
    header[6] = (byte)((totalDataLen >> 16) & 0xff);
    header[7] = (byte)((totalDataLen >> 24) & 0xff);
    header[8] = 'W';
    header[9] = 'A';
    header[10] = 'V';
    header[11] = 'E';
    header[12] = 'f';
    header[13] = 'm';
    header[14] = 't';
    header[15] = ' ';
    header[16] = 16;
    header[17] = 0;
    header[18] = 0;
    header[19] = 0;
    header[20] = 1;
    header[21] = 0;
    header[22] = (byte) channels;
    header[23] = 0;
    header[24] = (byte)(longSampleRate & 0xff);
    header[25] = (byte)((longSampleRate >> 8) & 0xff);
    header[26] = (byte)((longSampleRate >> 16) & 0xff);
    header[27] = (byte)((longSampleRate >> 24) & 0xff);
    header[28] = (byte)(byteRate & 0xff);
    header[29] = (byte)((byteRate >> 8) & 0xff);
    header[30] = (byte)((byteRate >> 16) & 0xff);
    header[31] = (byte)((byteRate >> 24) & 0xff);
    header[32] = (byte)(2 * 16 / 8);
    header[33] = 0;
    header[34] = RECORDER_BPP;
    header[35] = 0;
    header[36] = 'd';
    header[37] = 'a';
    header[38] = 't';
    header[39] = 'a';
    header[40] = (byte)(totalAudioLen & 0xff);
    header[41] = (byte)((totalAudioLen >> 8) & 0xff);
    header[42] = (byte)((totalAudioLen >> 16) & 0xff);
    header[43] = (byte)((totalAudioLen >> 24) & 0xff);

    out.write(header, 0, 44);
}
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  • Vipul thanx的片段.RECORDER_SAMPLERATE和RECORDER_BPP是什么意思?如果它们是恒定的而不是必须的值? (3认同)
  • 哎呀:这段代码中有很多错误!1.它不解析输入文件的标题,而是将标题视为音频数据.2.它假定它总能成功读取输入文件中的缓冲区数据.3.它假定输入文件具有指定的格式. (2认同)