你如何从/ dev/input/mice中读取鼠标按钮状态？

Question

你如何从/ dev/input/mice中读取鼠标按钮状态？我想检测按钮是否被按下.

Answer 1

您可以打开设备并从中读取./ dev/input/mice中的事件长度为3个字节,需要进行一些解析.我认为现在首选的方法是使用/ dev/input/event#.但是,这是一个使用/ dev/input/mice的小例子.

#include <stdio.h>
#include <unistd.h>
#include <fcntl.h>

int main(int argc, char** argv)
{
    int fd, bytes;
    unsigned char data[3];

    const char *pDevice = "/dev/input/mice";

    // Open Mouse
    fd = open(pDevice, O_RDWR);
    if(fd == -1)
    {
        printf("ERROR Opening %s\n", pDevice);
        return -1;
    }

    int left, middle, right;
    signed char x, y;
    while(1)
    {
        // Read Mouse     
        bytes = read(fd, data, sizeof(data));

        if(bytes > 0)
        {
            left = data[0] & 0x1;
            right = data[0] & 0x2;
            middle = data[0] & 0x4;

            x = data[1];
            y = data[2];
            printf("x=%d, y=%d, left=%d, middle=%d, right=%d\n", x, y, left, middle, right);
        }   
    }
    return 0; 
}

单击鼠标即可生成:

x=0, y=0, left=1, middle=0, right=0
x=0, y=0, left=0, middle=0, right=0

并且一个鼠标移动(注意"相对"鼠标移动坐标):

x=1, y=1, left=0, middle=0, right=0