在Android App上接收短信

Question

我按照教程接收我的应用程序上的短信并阅读它以将SMSbody传递给Toast.那是Receiver类.

public class SmsReciever extends BroadcastReceiver {
        @Override
        public void onReceive(Context context, Intent intent){
        Bundle bundle= intent.getExtras();
        SmsMessage[] msgs= null;
        String str="";
        if(bundle != null ){
            Object [] pdus=(Object[]) bundle.get("pdus");
            msgs=new SmsMessage[pdus.length];
            for(int i=0; i< msgs.length;i++){
                msgs[i]= SmsMessage.createFromPdu((byte[])pdus[i]);
                str+= msgs[i].getMessageBody();

            }
             Toast.makeText(context, str, Toast.LENGTH_LONG).show();
        }
        }

    }

清单文件

    <receiver android:name="com.msoft.masrooq.SmsReciever">
    <intent-filter>
    <action android:name="android.provider.telephony.SMS_RECIEVED"></action>
    </intent-filter>
    </receiver>
        <uses-permission android:name="android.permission.RECEIVE_SMS"/>
            <uses-permission android:name="android.permission.READ_SMS" />

该应用程序启动正常,但它没有响应接收短信它没有做任何事情.

Answer 1

这是我接收短信的实现.短信可以分成很多,注意它是如何处理的.还要检查android:priority属性.

public class SmsReceiver extends BroadcastReceiver {

    private static final String SMS_RECEIVED = "android.provider.Telephony.SMS_RECEIVED";

    @Override
    public void onReceive(Context context, Intent intent) {
        if (intent.getAction().equals(SMS_RECEIVED)) {
            Bundle bundle = intent.getExtras();
            if (bundle != null) {
                // get sms objects
                Object[] pdus = (Object[]) bundle.get("pdus");
                if (pdus.length == 0) {
                    return;
                }
                // large message might be broken into many
                SmsMessage[] messages = new SmsMessage[pdus.length];
                StringBuilder sb = new StringBuilder();
                for (int i = 0; i < pdus.length; i++) {
                    messages[i] = SmsMessage.createFromPdu((byte[]) pdus[i]);
                    sb.append(messages[i].getMessageBody());
                }
                String sender = messages[0].getOriginatingAddress();
                String message = sb.toString();
                Toast.makeText(context, message, Toast.LENGTH_SHORT).show();
                // prevent any other broadcast receivers from receiving broadcast
                // abortBroadcast();
            }
        }
    }
}

AndroidManifest.xml中

<?xml version="1.0" encoding="utf-8"?>
<manifest xmlns:android="http://schemas.android.com/apk/res/android"
    package="com.example.smsreceiver"
    android:versionCode="1"
    android:versionName="1.0">
    <uses-sdk android:minSdkVersion="4" />
    <uses-permission android:name="android.permission.RECEIVE_SMS" />
    <application android:icon="@drawable/icon" android:label="@string/app_name">
        <activity
            android:name=".SmsLoggerActivity"
            android:label="@string/app_name">
            <intent-filter>
                <action android:name="android.intent.action.MAIN" />
                <category android:name="android.intent.category.LAUNCHER" />
            </intent-filter>
        </activity>
        <receiver android:name="com.example.smsreceiver.SmsReceiver" android:enabled="true">
            <intent-filter android:priority="2147483647">
                <action android:name="android.provider.Telephony.SMS_RECEIVED" />
            </intent-filter>
        </receiver>
    </application>
</manifest>

几点注意事项:如果你声明你的接收器在xml而不是系统可以使用你的接收器,无论你的应用程序是否已经启动.由于关于收到的短信息的Android 1.6通知是作为有序广播传送的,你可以使用android:priority属性<intent-filter>告诉系统首先将短信发送到你的应用程序(你也可以调用abortBroadcast(),以便其他应用程序不会收到短信,例如本地短信应用程序).不要忘记广播接收器有大约10秒的时间来执行其操作,否则它可能会在完成其工作之前提前终止.