Ham*_*eni 9 java string right-to-left
我正在尝试创建一种方法来检测Java中从右到左书写的字符串.我想出了这个问题做的在C#中类似的东西.
现在我需要有类似的东西,但用Java编写.
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Ham*_*eni 11
我想出了以下代码:
char[] chars = s.toCharArray();
for(char c: chars){
    if(c >= 0x600 && c <= 0x6ff){
        //Text contains RTL character
        break;
     }
}
它不是一种非常有效的方式,也不是一种准确的方法,但可以给出一个想法.
问题很老但也许别人可能有同样的问题......
在尝试了几个解决方案后,我找到了适合我的解决方案:
if (Character.getDirectionality(string.charAt(0)) == Character.DIRECTIONALITY_RIGHT_TO_LEFT
    || Character.getDirectionality(string.charAt(0)) == Character.DIRECTIONALITY_RIGHT_TO_LEFT_ARABIC
    || Character.getDirectionality(string.charAt(0)) == Character.DIRECTIONALITY_RIGHT_TO_LEFT_EMBEDDING
    || Character.getDirectionality(string.charAt(0)) == Character.DIRECTIONALITY_RIGHT_TO_LEFT_OVERRIDE
    ) {
    // it is a RTL string
}
这是 Darko 答案的改进版本:
public static boolean isRtl(String string) {
    if (string == null) {
        return false;
    }
    for (int i = 0, n = string.length(); i < n; ++i) {
        byte d = Character.getDirectionality(string.charAt(i));
        switch (d) {
            case DIRECTIONALITY_RIGHT_TO_LEFT:
            case DIRECTIONALITY_RIGHT_TO_LEFT_ARABIC:
            case DIRECTIONALITY_RIGHT_TO_LEFT_EMBEDDING:
            case DIRECTIONALITY_RIGHT_TO_LEFT_OVERRIDE:
                return true;
            case DIRECTIONALITY_LEFT_TO_RIGHT:
            case DIRECTIONALITY_LEFT_TO_RIGHT_EMBEDDING:
            case DIRECTIONALITY_LEFT_TO_RIGHT_OVERRIDE:
                return false;
        }
    }
    return false;
}
此代码适用于以下所有情况:
???? ???               => true
good morning ???? ???  => false
???? ??? good morning  => true
good ???? ??? morning  => false
???? good morning ???  => true
(???? ???)             => true
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