从列mysql中删除所有数字字符

Question

我想开发一个mysql函数,只能从字符串中删除数字字符.

Answer 1

您可以编写用户定义的函数,您可以在其中编写替换逻辑,或者您可以尝试:

Replace(Replace(Replace(Replace(Replace(Replace(Replace(Replace(Replace(Replace(column,'9',''),'8',''),'7',''),'6',''),'5',''),'4',''),'3',''),'2',''),'1',''),'0','')

Answer 2

创建功能来完成此任务.

DROP FUNCTION IF EXISTS alphas; 
DELIMITER | 
CREATE FUNCTION alphas( str CHAR(32) ) RETURNS CHAR(16) 
BEGIN 
  DECLARE i, len SMALLINT DEFAULT 1; 
  DECLARE ret CHAR(32) DEFAULT ''; 
  DECLARE c CHAR(1); 
  SET len = CHAR_LENGTH( str ); 
  REPEAT 
    BEGIN 
      SET c = MID( str, i, 1 ); 
      IF c REGEXP '[[:alpha:]]' THEN 
        SET ret=CONCAT(ret,c); 
      END IF; 
      SET i = i + 1; 
    END; 
  UNTIL i > len END REPEAT; 
  RETURN ret; 
END | 
DELIMITER ; 
SELECT alphas('123ab45cde6789fg'); 
+----------------------------+ 
| alphas('123ab45cde6789fg') | 
+----------------------------+ 
| abcdefg                    | 
+----------------------------+ 

如果您只想要数字,请使用此选项

SET GLOBAL log_bin_trust_function_creators=1; 
DROP FUNCTION IF EXISTS digits; 
DELIMITER | 
CREATE FUNCTION digits( str CHAR(32) ) RETURNS CHAR(32) 
BEGIN 
  DECLARE i, len SMALLINT DEFAULT 1; 
  DECLARE ret CHAR(32) DEFAULT ''; 
  DECLARE c CHAR(1); 
  SET len = CHAR_LENGTH( str ); 
  REPEAT 
    BEGIN 
      SET c = MID( str, i, 1 ); 
      IF c BETWEEN '0' AND '9' THEN  
        SET ret=CONCAT(ret,c); 
      END IF; 
      SET i = i + 1; 
    END; 
  UNTIL i > len END REPEAT; 
  RETURN ret; 
END | 
DELIMITER ; 

SELECT digits('123ab45cde6789fg'); 
+----------------------------+ 
| digits('123ab45cde6789fg') | 
+----------------------------+ 
| 123456789                  | 
+----------------------------+ 

参考