hibernate oracle标识符太长ORA-00972

Question

我坚持这个问题.数据库架构由其他人提供,所以我不能简单地更改名称.我尝试在任何地方添加适当的注释,也许我错过了一些东西(显而易见)？

这是我的完整映射(很多classess),我会省略getter/setter.

问题是当hibernate试图获得所有 List<ControlRuleAttrib> controlRuleAttribs

控制规则

@Entity
@Table(name = "CONTROL_RULE")
public class ControlRule implements Serializable {
 @Id
 @GeneratedValue(strategy = GenerationType.IDENTITY)
 @Column(name = "CONTROL_RULE_ID")
 private Long id;
 @ManyToOne(fetch = FetchType.LAZY)
 @Cascade(CascadeType.ALL)
 @JoinColumn(name = "CONTROL_RULE_TYPE_ID")
 @ForeignKey(name = "CONTROL_RULE_TYPE_ID")
 private ControlRuleType controlRuleType;
 @Column(name = "JOB_NM")
 private String jobname;
 @Column(name = "LIBRARY_NM")
 private String libraryname;
 @Column(name = "TABLE_NM")
 private String tablename;
 @Column(name = "COLUMN_NM")
 private String columnname;

 @OneToMany(fetch = FetchType.LAZY)
 @Cascade(CascadeType.ALL)
 @JoinTable(name = "CONTROL_RULE_ATTRIB", joinColumns = {
  @JoinColumn(name = "CONTROL_RULE_ID", nullable = false, updatable = false)
 })
 private List < ControlRuleAttrib > controlRuleAttribs;
}

ControlRuleAttrib

@Table(name = "CONTROL_RULE_ATTRIB")
@Entity
public class ControlRuleAttrib {
 @EmbeddedId
 private ControlRuleAttribPK controlRuleAttribPK;

 @Column(name = "ATTRIBUTE_VALUE")
 private String attributeValue;
}

ControleRuleAttribPK 这里的问题是,是否有可能以某种方式得到实体ControlRuleAttribType的ControlRuleAttrib？正如你在下面看到的ControlRuleAttribTypeId是id ControleRuleAttribType.我想得到整个对象isteand的整数.

@Embeddable
public class ControlRuleAttribPK implements Serializable {
 @Column(name = "CONTROL_RULE_ID")
 private Long controlRuleId;

 @Column(name = "ATTRIBUTE_SEQ_NUM")
 private Integer attributeSeqNum;

 @Column(name = "CONTROL_RULE_ATTRIB_TYPE_ID")
 private Integer controlRuleAttribTypeId;
}

ControleRuleAttribType

@Entity
@Table(name = "CONTROL_RULE_ATTRIB_TYPE")
public class ControlRuleAttribType implements Serializable {
 @Id
 @GeneratedValue(strategy = GenerationType.IDENTITY)
 @Column(name = "CONTROL_RULE_ATTRIB_TYPE_ID")
 private Integer id;
 @Column(name = "CONTROL_RULE_ATTRIB_TYPE_NM")
 private String typename;
 @Column(name = "CONTROL_RULE_ATTRIB_TYPE_DESC")
 private String typedesc;

 @ManyToOne(fetch = FetchType.LAZY)
 @Cascade(CascadeType.ALL)
 @JoinColumn(name = "CONTROL_RULE_TYPE_ID")
 @ForeignKey(name = "CONTROL_RULE_TYPE_ID")
 private ControlRuleType controlruletype;
}

ControleRuleType

@Entity
@Table(name = "CONTROL_RULE_TYPE")
public class ControlRuleType implements Serializable {
 @Id
 @GeneratedValue(strategy = GenerationType.IDENTITY)
 @Column(name = "CONTROL_RULE_TYPE_ID")
 private Integer id;
 @Column(name = "CONTROL_RULE_TYPE_NM")
 private String typename;
 @Column(name = "CONTROL_RULE_TYPE_DESC")
 private String typedesc;
}

编辑

这是stacktrace:

https://gist.github.com/a30dd9ce534d96bb9a97

你会发现,它在这里失败了:

在com.execon.controllers.main.MainPageController.getMainPage(MainPageController.java:33)[classes:]

这就是:

List<ControlRule> list = SessionFactoryUtils.openSession(
    sessionFactory ).createQuery( "from ControlRule" ).list();
System.out.println( list );

我添加的映射的每个对象都有如下toString()声明的方法:

@Override
public String toString()
{
    String s = "ControlRule{";
    s += "id=" + id.toString();
    s += ", controlRuleType=" + controlRuleType;
    s += ", jobname='" + jobname + '\'';
    s += ", libraryname='" + libraryname + '\'';
    s += ", tablename='" + tablename + '\'';
    s += ", columnname='" + columnname + '\'';
    s += ", controlRuleAttribs=" + controlRuleAttribs;
    s += '}';
    return s;
}

和hibernate请求:

https://gist.github.com/c8584113522757a4e0d8/4f31dc03e7e842eef693fa7ba928e19d27b3ca26

请帮忙 :)

编辑2

在阅读@Jens回答后,我对代码进行了一些更改.首先,我按你所写的做了,它给出了错误:

org.hibernate.AnnotationException:从com.execon.models.controlrules.ControlRule引用com.execon.models.controlrules.ControlRuleAttrib的外键具有错误的列数.应该是3

我想这是对的,因为我有复合主键.

然后我这样试了:

@OneToMany(fetch = FetchType.LAZY)
@Cascade(CascadeType.ALL)
@JoinTable(name = "CONTROL_RULE_ATTRIB",
        joinColumns = {
                @JoinColumn(name = "CONTROL_RULE_ID", nullable = false, updatable = false)
        },
        inverseJoinColumns = {
                @JoinColumn(name = "CONTROL_RULE_ID", nullable = false, updatable = false),
                @JoinColumn(name = "CONTROL_RULE_ATTRIB_TYPE_ID", nullable = false, updatable = false),
                @JoinColumn(name = "ATTRIBUTE_SEQ_NUM", nullable = false, updatable = false)
        })
private List<ControlRuleAttrib> controlRuleAttribs;

很接近,但它给了我以下例外:

映射中的重复列用于收集..

所以最后我删除了

joinColumns = 
{
    @JoinColumn(name = "CONTROL_RULE_ID", nullable = false, updatable = false)
}

除了当我尝试访问集合时,Hibernate正在进行以下查询:

https://gist.github.com/c88684392f0b7a62bea5

最后一行是controlrul0_.CONTROL_RULE_CONTROL_RULE_ID=?应该的controlrul0_.CONTROL_RULE_ID=?.

无论如何我能使它工作吗？:/

Answer 1

经过过去几个小时的努力，我终于让它在我的项目中发挥作用。我所做的事情是这样的：

控制规则

@OneToMany(fetch = FetchType.LAZY, mappedBy = "controlRuleAttribPK.controlRuleId")
@Cascade(CascadeType.ALL)
private List<ControlRuleAttrib> controlRuleAttribs;

基本上指出集合应该使用复合主键中的controlRuleId。到目前为止，它工作得很好！