ShouldSerialize模式和DataContractSerializer

M.E*_*.E. 4 c# datacontractserializer

有没有办法让ShouldSerialize*模式合作DataContractSerializer

这是一个小例子:

我有一个简单的类Person,看起来像这样:

[DataContract]
public class Person
{
  [DataMember]
  public string FirstName { get; set; }
  public bool ShouldSerializeFirstName()
  {
    return !string.IsNullOrEmpty(FirstName);
  }

  [DataMember]
  public string LastName { get; set; }
  public bool ShouldSerializeLastName()
  {
    return !string.IsNullOrEmpty(LastName);
  }

  public Person(string firstName, string lastName)
  {
    FirstName = firstName;
    LastName = lastName;
  }
  public Person(string firstName)
  {
    FirstName = firstName;
  }
  public Person()
  {
  }
}
Run Code Online (Sandbox Code Playgroud)

FirstName或者LastName只有在它们不为空或空时才应序列化.这适用XmlSerializerDataContractSerializer似乎忽略了ShouldSerialize模式.该*Specified模式也不起作用.

我正在创建两个不同的Xml文件.一个使用DataContractSerializer,一个使用XmlSerializer:

List<Person> persons = new List<Person>();
persons.Add (new Person("John", "Doe"));
persons.Add (new Person("Carl"));

DataContractSerializer serializer = new DataContractSerializer (typeof (List<Person>));
using (XmlWriter writer = XmlWriter.Create(@"c:\test1.xml", settings))
{
  serializer.WriteObject (writer, persons);
}

XmlSerializer xmlSerializer = new XmlSerializer (typeof (List<Person>));
XmlWriter xmlWriter = XmlWriter.Create (@"c:\text2.xml", settings);
xmlSerializer.Serialize (xmlWriter, persons);
xmlWriter.Close();
Run Code Online (Sandbox Code Playgroud)

文件test1.xml(DataContractSerializer)的输出如下所示:

<?xml version="1.0" encoding="utf-8"?>
<ArrayOfPerson xmlns:i="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://schemas.datacontract.org/2004/07/XmlSerialization">
  <Person>
    <FirstName>John</FirstName>
    <LastName>Doe</LastName>
  </Person>
  <Person>
    <FirstName>Carl</FirstName>
    <LastName i:nil="true" />
  </Person>
</ArrayOfPerson>
Run Code Online (Sandbox Code Playgroud)

文件test2.xml(XmlSerializer)的输出如下所示:

<?xml version="1.0" encoding="utf-8"?>
<ArrayOfPerson xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
  <Person>
    <FirstName>John</FirstName>
    <LastName>Doe</LastName>
  </Person>
  <Person>
    <FirstName>Carl</FirstName>
  </Person>
</ArrayOfPerson>
Run Code Online (Sandbox Code Playgroud)

Eri*_*sot 5

AFAIK,ShouldSerialize*不适用于datacontract序列化程序.凯文的答案毫无用处.你可以删除它.不幸的是,只有处理空值才能使代码有效.

这是一个更通用的解决方案:它根据给定条件返回空值.

    [DataContract]
    public class Person
    {
      private string firstName;
      [DataMember(IsRequired = false, EmitDefaultValue = false)]
      public string FirstName
      {
        get
        {
            //Put here any condition for serializing
            return string.IsNullOrWhiteSpace(firstName) ? null : firstName;
        }
        set
        {
            firstName = value;
        }
      }
    }
Run Code Online (Sandbox Code Playgroud)