Pav*_*nen 2 xcode gesture swipe ios
在我的viewDidLoad我设置
UISwipeGestureRecognizer *swipeRecognizerU = [[UISwipeGestureRecognizer alloc] initWithTarget:self action:@selector(swipeUpDetected:)]; swipeRecognizerU.direction = UISwipeGestureRecognizerDirectionUp; [self.view addGestureRecognizer:swipeRecognizerU];
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当我通过弹出窗口加载新视图时,我需要禁用该手势
// show popup view
-(IBAction)showPopup:(id)sender
{
MJDetailViewController *detailViewController = [[MJDetailViewController alloc] initWithNibName:@"MJDetailViewController" bundle:nil];
[self presentPopupViewController:detailViewController animationType:MJPopupViewAnimationSlideBottomBottom];
}
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在弹出视图被解除后,我需要设置滑动手势.
// hide popup view
-(IBAction)hidePopup:(id)sender
{
[self dismissPopupViewControllerWithanimationType:MJPopupViewAnimationSlideBottomBottom];
}
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怎么做到这一点?
我认为有一个名为enabled的属性UIGestureRecognizer.你试试这个,应该可以禁用你的滑动:
swipeGestureRecognizer.enabled = NO;
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