Ken*_*ral 6 c# math permutation combinatorics
如何更改下面的C#代码以列出所有可能的排列而不重复?例如:2个骰子卷的结果将产生1,1,2,因此不应出现2,1,1.
以下是我的代码:
string[] Permutate(int input)
{
string[] dice;
int numberOfDice = input;
const int diceFace = 6;
dice = new string[(int)Math.Pow(diceFace, numberOfDice)];
int indexNumber = (int)Math.Pow(diceFace, numberOfDice);
int range = (int)Math.Pow(diceFace, numberOfDice) / 6;
int diceNumber = 1;
int counter = 0;
for (int i = 1; i <= indexNumber; i++)
{
if (range != 0)
{
dice[i - 1] += diceNumber + " ";
counter++;
if (counter == range)
{
counter = 0;
diceNumber++;
}
if (i == indexNumber)
{
range /= 6;
i = 0;
}
if (diceNumber == 7)
{
diceNumber = 1;
}
}
Thread.Sleep(1);
}
return dice;
}
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我能想到的最简单的方式:
List<string> dices = new List<string>();
for (int i = 1; i <= 6; i++)
{
for (int j = i; j <= 6; j++)
{
for (int k = j; k <= 6; k++)
{
dices.Add(string.Format("{0} {1} {2}", i, j, k));
}
}
}
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我数学也不好,这可能有帮助,也可能没有帮助......
程序.cs
namespace Permutation
{
using System;
using System.Collections.Generic;
class Program
{
static void Main(string[] args)
{
Console.WriteLine("Generating list.");
var dice = new List<ThreeDice>();
for (int x = 1; x <= 6; x++)
{
for (int y = 1; y <= 6; y++)
{
for (int z = 1; z <= 6; z++)
{
var die = new ThreeDice(x, y, z);
if (dice.Contains(die))
{
Console.WriteLine(die + " already exists.");
}
else
{
dice.Add(die);
}
}
}
}
Console.WriteLine(dice.Count + " permutations generated.");
foreach (var die in dice)
{
Console.WriteLine(die);
}
Console.ReadKey();
}
}
}
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ThreeDice.cs
namespace Permutation
{
using System;
using System.Collections.Generic;
public class ThreeDice : IEquatable<ThreeDice>
{
public ThreeDice(int dice1, int dice2, int dice3)
{
this.Dice = new int[3];
this.Dice[0] = dice1;
this.Dice[1] = dice2;
this.Dice[2] = dice3;
}
public int[] Dice { get; private set; }
// IEquatable implements this method. List.Contains() will use this method to see if there's a match.
public bool Equals(ThreeDice other)
{
// Get the current dice values into a list.
var currentDice = new List<int>(this.Dice);
// Check to see if the same values exist by removing them one by one.
foreach (int die in other.Dice)
{
currentDice.Remove(die);
}
// If the list is empty, we have a match.
return currentDice.Count == 0;
}
public override string ToString()
{
return "<" + this.Dice[0] + "," + this.Dice[1] + "," + this.Dice[2] + ">";
}
}
}
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祝你好运。