Pab*_*buc 6 sql-server stored-procedures sql-server-2008-r2
我的数据如下:
ID LENGTH_IN_CM
1 1.0
2 1.0
3 9.0
4 5.0
5 15.0
6 3.0
7 5.0
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我知道页面长20厘米,想要计算每个项目将在哪些页面上.
因此,例如id为1,2,3和4的项目将位于第一页(1.0 + 1.0 + 9.0 + 5.0 <20.0),但5和6将在第二页上,7在第三页上.
是否可以在不使用光标的情况下计算页码?
好吧,我为挑战做了更多,因为我认为这是一个好主意.我倾向于相信Aaron光标可能更合适.无论如何:
declare @Items table (ID int not null,LENGTH_IN_CM decimal(5,1) not null)
insert into @Items(ID,LENGTH_IN_CM) values
(1,1.0),
(2,1.0),
(3,9.0),
(4,5.0),
(5,15.0),
(6,3.0),
(7,6.0)
;With PossiblePages as (
select ID as MinID,ID as MaxID,LENGTH_IN_CM as TotalLength from @Items
union all
select MinID,MaxID + 1,CONVERT(decimal(5,1),TotalLength + LENGTH_IN_CM)
from
PossiblePages pp
inner join
@Items it
on
pp.MaxID + 1 = it.ID
where
TotalLength + LENGTH_IN_CM <= 20.0
), LongPages as (
select MinID,MAX(MaxID) as MaxID,MAX(TotalLength) as TotalLength from PossiblePages group by MinID
), FinalPages as (
select MinID,MaxID,TotalLength from LongPages where MinID = 1
union all
select lp.MinID,lp.MaxID,lp.TotalLength
from
LongPages lp
inner join
FinalPages fp
on
lp.MinID = fp.MaxID + 1
), PageNumbers as (
select MinID,MaxID,ROW_NUMBER() OVER (ORDER BY MinID) as PageNo
from FinalPages
)
select * from PageNumbers
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结果:
MinID MaxID PageNo
----------- ----------- --------------------
1 4 1
5 6 2
7 7 3
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如果要为每行分配页码,哪个应该很容易连接回原始表.
PossiblePages 计算每个可能的页面 - 对于每一行,它就好像该行是该页面上的第一行,然后确定可以追加多少行,以及该行范围所代表的总长度(可能是更清晰的方法来计算这个表达式,目前还不确定).
LongPages然后PossiblePages为每个起始行号找到计算的最长值.
最后,FinalPages从第一页开始(逻辑上,必须是以1开头的那一页ID- 如果你不能保证从1开始,并且需要找到最早的那个,你总是可以引入另一个计算).然后,下一页是从比前一行高一行的行ID开始的页面.
你不需要 PageNumbers,但正如我所说,我正在考虑加入原来的表格.
正如评论者预测的那样,我认为这不会很好 - 只是在样本上,我看到至少有4个表扫描才能计算出来.
奖金疯狂.这个只扫描表3次:
;With PageRows as (
select ID as MinID,ID as MaxID,LENGTH_IN_CM as TotalLength from @Items where ID=1
union all
select MinID,MaxID + 1,CONVERT(decimal(5,1),TotalLength + LENGTH_IN_CM)
from
PageRows pr
inner join
@Items ir
on
pr.MaxID = ir.ID-1
where
TotalLength + LENGTH_IN_CM <= 20.0
union all
select ir.ID as MinID,ir.ID as MaxID,ir.LENGTH_IN_CM as TotalLength
from
PageRows pr
inner join
@Items ir
on
pr.MaxID = ir.ID-1
where
TotalLength + LENGTH_IN_CM > 20.0
), PageNumbers as (
select MinID,MAX(MaxID) as MaxID,ROW_NUMBER() OVER (ORDER BY MinID) as PageNo
from PageRows
group by MinID
)
select * from PageNumbers
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