如何在rails上的ruby上传文件?

Viv*_*ech 19 file-upload ruby-on-rails ruby-on-rails-3

我在铁轨上的红宝石很新.我遇到了问题.我想创建一个文件上传功能,通过它我可以上传任何类型的文件(文本,图像等).我的控制器文件是(upload_controller.rb):

class UploadController < ApplicationController
def index
    render :file => 'app\views\upload\uploadfile.html.erb'
end
def uploadFile
    post = DataFile.save(params[:upload])
    render :text => "File has been uploaded successfully"
end
end
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我的模型文件是(data_file.rb):

class DataFile < ActiveRecord::Base
    attr_accessor :upload
  def self.save(upload)
    name = upload['datafile'].original_filename
    directory = 'public/data'
    # create the file path
    path = File.join(directory,name)
    # write the file
    File.open(path, "wp") { |f| f.write(upload['datafile'].read)}
  end
end
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我的View文件是(uploadfile.html.erb):

<h1>File Upload</h1>
<%= form_tag({:action => 'uploadFile'}, :multipart => true) do %>
<p><label for="upload_file">Select File</label>
<%= file_field 'upload', 'datafile' %></p>
<%= submit_tag "Upload" %>
<% end %>
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现在,当我尝试上传图像时,我在模型文件中收到错误"无效访问模式wp".当我在模型文件中将File.open(path,"wp")更改为File.open(path,"w")时,这会将"'\ x89'从ASCII-8BIT更改为UTF-8".对于.txt文件,它工作正常.我正在使用ruby 1.9.3和rails 3.2.6

use*_*717 8

谢谢你,我也研究过rails!

它适用于rails 3.1

我的代码:

Routes
resources :images do
      collection { post :upload_image }
    end
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调节器

class ImagesController < ApplicationController
  def index
    @car = Car.find(params[:car_id])
    @images = @car.images.order("order_id")
  end

  def upload_image   
    DataFile.save_file(params[:upload])
    redirect_to images_path(:car_id => params[:car_id])
  end
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查看index.html.erb

<h1>File Upload</h1>
  <%= form_tag({:action => 'upload_image', :car_id => @car.id}, :multipart => true) do %>
    <p><label for="upload_file">Select File</label>
    <%= file_field 'upload', 'datafile' %></p>
    <%= submit_tag "Upload" %>
  <% end %>

  <% @images.each do |image| %>
     <%= image.id %><br/>
     <%= image.name %>
  <% end %>
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模型

class DataFile < ActiveRecord::Base
    attr_accessor :upload

  def self.save_file(upload)   

    file_name = upload['datafile'].original_filename  if  (upload['datafile'] !='')    
    file = upload['datafile'].read    

    file_type = file_name.split('.').last
    new_name_file = Time.now.to_i
    name_folder = new_name_file
    new_file_name_with_type = "#{new_name_file}." + file_type

    image_root = "#{RAILS_CAR_IMAGES}"


    Dir.mkdir(image_root + "#{name_folder}");
      File.open(image_root + "#{name_folder}/" + new_file_name_with_type, "wb")  do |f|  
        f.write(file) 
      end

  end
end
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Kas*_*yap 3

问题的原因是编码问题。您似乎正在以 ASCII-8BIT 模式读取文件并以 UTF-8 写入文件,这意味着需要进行转换。从 ASCII-8BIT 到 UTF-8 的转换并不简单。或者,您可以指定二进制模式来读取和写入文件。

upload_file = File.new(<original file>, "rb").read
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File.open(<final uploaded file>, "wb") {|f| f.write(upload_file) }
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