Nug*_*get 18 iphone json objective-c ios afnetworking
编辑07/14
正如比尔·伯吉斯在他回答的评论mentionned,这个问题是有关version 1.3的AFNetworking.这里的新人可能已经过时了.
我对iPhone开发很新,我使用AFNetworking作为我的服务库.
我正在查询的API是RESTful的,我需要发出POST请求.为此,我尝试使用以下代码:
NSDictionary *parameters = [NSDictionary dictionaryWithObjectsAndKeys:@"my_username", @"username", @"my_password", @"password", nil];
NSURL *url = [NSURL URLWithString:@"http://localhost:8080/login"];
NSURLRequest *request = [NSURLRequest requestWithURL:url];
AFJSONRequestOperation *operation = [AFJSONRequestOperation JSONRequestOperationWithRequest:request success:^(NSURLRequest *request, NSHTTPURLResponse *response, id JSON) {
NSLog(@"Pass Response = %@", JSON);
} failure:^(NSURLRequest *request, NSHTTPURLResponse *response, NSError *error, id JSON) {
NSLog(@"Failed Response : %@", JSON);
}];
[operation start];
Run Code Online (Sandbox Code Playgroud)
此代码有两个主要问题:
AFJSONRequestOperation似乎提出了一个GET请求,而不是一个请求POST.我也尝试过这段代码:
NSDictionary *parameters = [NSDictionary dictionaryWithObjectsAndKeys:@"my_username", @"username", @"my_password", @"password", nil];
NSURL *url = [NSURL URLWithString:@"http://localhost:8080"];
AFHTTPClient *httpClient = [[AFHTTPClient alloc] initWithBaseURL:url];
[httpClient postPath:@"/login" parameters:parameters success:^(AFHTTPRequestOperation *operation, id responseObject) {
NSLog(@"Succes : %@", responseObject);
} failure:^(AFHTTPRequestOperation *operation, NSError *error) {
NSLog(@"Failure : %@", error);
}];
Run Code Online (Sandbox Code Playgroud)
有没有更好的方法来制作我想要的东西来完成它?
谢谢您的帮助 !
Bil*_*ess 24
您可以覆盖正在使用的请求的默认行为AFNetworking以作为POST进行处理.
NSURLRequest *request = [client requestWithMethod:@"POST" path:path parameters:nil];
Run Code Online (Sandbox Code Playgroud)
这假设您已覆盖默认AFNetworking设置以使用自定义客户端.如果你不是,我会建议你这样做.只需创建一个自定义类来为您处理网络客户端.
MyAPIClient.h
#import <Foundation/Foundation.h>
#import "AFHTTPClient.h"
@interface MyAPIClient : AFHTTPClient
+(MyAPIClient *)sharedClient;
@end
Run Code Online (Sandbox Code Playgroud)
MyAPIClient.m
@implementation MyAPIClient
+(MyAPIClient *)sharedClient {
static MyAPIClient *_sharedClient = nil;
static dispatch_once_t oncePredicate;
dispatch_once(&oncePredicate, ^{
_sharedClient = [[self alloc] initWithBaseURL:[NSURL URLWithString:webAddress]];
});
return _sharedClient;
}
-(id)initWithBaseURL:(NSURL *)url {
self = [super initWithBaseURL:url];
if (!self) {
return nil;
}
[self registerHTTPOperationClass:[AFJSONRequestOperation class]];
[self setDefaultHeader:@"Accept" value:@"application/json"];
self.parameterEncoding = AFJSONParameterEncoding;
return self;
}
Run Code Online (Sandbox Code Playgroud)
然后,您应该可以在操作队列上启动网络调用,没有任何问题.
MyAPIClient *client = [MyAPIClient sharedClient];
[[AFNetworkActivityIndicatorManager sharedManager] setEnabled:YES];
[[AFNetworkActivityIndicatorManager sharedManager] incrementActivityCount];
NSString *path = [NSString stringWithFormat:@"myapipath/?value=%@", value];
NSURLRequest *request = [client requestWithMethod:@"POST" path:path parameters:nil];
AFJSONRequestOperation *operation = [AFJSONRequestOperation JSONRequestOperationWithRequest:request success:^(NSURLRequest *request, NSHTTPURLResponse *response, id JSON) {
// code for successful return goes here
[[AFNetworkActivityIndicatorManager sharedManager] decrementActivityCount];
// do something with return data
}failure:^(NSURLRequest *request, NSHTTPURLResponse *response, NSError *error, id JSON) {
// code for failed request goes here
[[AFNetworkActivityIndicatorManager sharedManager] decrementActivityCount];
// do something on failure
}];
[operation start];
Run Code Online (Sandbox Code Playgroud)
| 归档时间: |
|
| 查看次数: |
29718 次 |
| 最近记录: |