用两个向量排序

Question

我想知道是否有可能,例如,a vector<string>和a vector<double>对应的对,vector<string>按字母顺序排序,同时保持对匹配.

我知道这可以通过创建一个包含两个值并只对其进行排序的类来完成,但我宁愿保留两个单独的向量.

有任何想法吗？

最终守则:

#include "std_lib_facilities.h"

struct Name_pairs
{
       vector<string>names;
       vector<double>ages;
       void quicksort(vector<string>& num, vector<double>& num2, int top, int bottom);
       int divide(vector<string>& array, vector<double>& array2, int top, int bottom);
       bool test();
       string read_names();
       double read_ages();
       void print();
};

string Name_pairs::read_names()
{
       string name;
     cout << "Enter name: ";
     cin >> name;
     names.push_back(name);
     return name;
}

double Name_pairs::read_ages()
{
     double age;
     cout << "Enter corresponding age: ";
     cin >> age;
     ages.push_back(age);
     cout << endl;
     return age;
}

int Name_pairs::divide(vector<string>& array, vector<double>& array2, int top, int bottom)
{
    string x = array[top];
    int i = top-1;
    int j = bottom+1;
    string temp;
    double temp2;
    do{
        do
        {
             j--;
             }while(x<array[j]);

        do
        {
             i++;
             }while(x>array[i]);

        if(i<j)
        {
               temp = array[i];
               temp2 = array2[i];
               array[i] = array[j];
               array2[i] = array2[j];
               array[j] = temp;
               array2[j] = temp2;
               }
               }while(i<j);
        return j;
}


void Name_pairs::quicksort(vector<string>& num, vector<double>& num2, int top, int bottom) // top is subscript of beginning of vector
{
     int middle;
     if(top < bottom)
     {
            middle = divide(num, num2, top, bottom);
            quicksort(num, num2, top, middle);
            quicksort(num, num2, middle+1, bottom);
            }
     return;
}

void Name_pairs::print()
{
     for(int i = 0; i < (names.size()-1) && i < (ages.size()-1); ++i)
             cout << names[i] << " , " << ages[i] << endl;
}

int main(){
    Name_pairs np;
    cout << "Enter names and ages. Use 0 to cancel.\n";
    bool finished = false;
    while(!finished){
    finished = "0" == np.read_names();
    finished = 0 == np.read_ages();}
    np.quicksort(np.names, np.ages, 0, (np.names.size()-2));
    np.print();
    keep_window_open();}

Answer 1

如果您自己手动对它们进行排序,则只需将双数组中的相应项目与通常执行的字符串数组中的项目交换即可.或者,您可以拥有第三个数组:

vector<unsigned int> indices;

它只是索引到字符串/ double数组,而是对该数组进行排序(根据字符串数组中的值进行交换).