use*_*192 5 objective-c nsmutablearray
我收到此错误:[NSMutableArray objectAtIndex:]: index 0 beyond bounds for empty array虽然我的数据库中有75个项目.为什么它会向我显示此错误?我正在尝试从我的数据库中获取项目,但它告诉我索引0.
+(NSMutableArray *)GetAttitudeItems
{
NSArray *arrDocPath = NSSearchPathForDirectoriesInDomains(NSDocumentDirectory, NSUserDomainMask, YES);
NSString *strDestPath = [NSString stringWithFormat:@"%@/ItemsAndCategory.sqlite",[arrDocPath objectAtIndex:0]];
//sqlite3 *sqlite;
NSMutableArray *arrItemsList;
if(sqlite3_open([strDestPath UTF8String],&database)==SQLITE_OK)
{
const char *strQuery = "SELECT * FROM Items WHERE CategoryName='ATTITUDE' ORDER BY RANDOM()";
NSLog(@"The value is %s",strQuery);
sqlite3_stmt *stmt;
//char *err;
arrItemsList = [[NSMutableArray alloc]init];
if(sqlite3_prepare_v2(database, strQuery , -1,&stmt, NULL)==SQLITE_OK)
{
while (sqlite3_step(stmt)==SQLITE_ROW)
{
NSString *StrCatename = [NSString stringWithUTF8String:(char*)sqlite3_column_text(stmt, 1)];
NSString *StrItemName = [NSString stringWithUTF8String:(char*)sqlite3_column_text(stmt, 0)];
Itemslist *itemlist = [[Itemslist alloc]init];
itemlist.CategoryValue = StrCatename;
itemlist.ItemValue =StrItemName;
[arrItemsList addObject:itemlist];
}
}
if (stmt!=nil)
{
sqlite3_finalize(stmt);
}
}
sqlite3_close(database);
return arrItemsList;
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}
如果您确信您的数据库调用应该返回数据,我将确保至少有一个 if () else () 语句实际上被命中。否则,鉴于您在上面初始化了它,您的数组是空的:
NSMutableArray *arrAlert = [[NSMutableArray alloc]init];
一个简单的自我检查方法是else在链的底部添加一条语句if else,并在那里断言某些内容(即,对于初学者来说,至少打印一些内容。)
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