线程“main”中的异常 java.lang.IllegalArgumentException：工作表索引 (0) 超出范围 (0..-1)

Question

我想使用 apache poi api 在 java 中读取 2010 excel 文件......但它给了我一个错误线程“main”中的异常 java.lang.IllegalArgumentException: Sheet index (0) is out of range (0..-1 ) 我正在使用 xssf 但如果我想从旧格式的 excel 中获取数据，那么它可以通过 HSSF 正常工作..我不知道 XSSF 发生了什么..这是我的代码..请帮助我。

import java.io.FileInputStream;
import java.io.FileNotFoundException;
import java.io.InputStream;
import java.util.Iterator;

import org.apache.poi.ss.usermodel.Cell;
import org.apache.poi.ss.usermodel.Row;
import org.apache.poi.xssf.usermodel.XSSFCell;
import org.apache.poi.xssf.usermodel.XSSFRichTextString;
import org.apache.poi.xssf.usermodel.XSSFRow;
import org.apache.poi.xssf.usermodel.XSSFSheet;
import org.apache.poi.xssf.usermodel.XSSFWorkbook;

/**
 * This java program is used to read the data from a Excel file and display them
 * on the console output.
 * 
 * @author dhanago
 */
public class xssff {

    /** Creates a new instance of POIExcelReader */
    public xssff() {
    }

    /**
     * This method is used to display the Excel content to command line.
     * 
     * @param xlsPath
     */
    @SuppressWarnings("unchecked")
    public void displayFromExcel(String xlsPath) {
        InputStream inputStream = null;

        try {
            inputStream = new FileInputStream(xlsPath);
        } catch (FileNotFoundException e) {
            System.out.println("File not found in the specified path.");
            e.printStackTrace();
        }


        XSSFWorkbook workBook = new XSSFWorkbook();
        XSSFSheet sheet = workBook.getSheetAt(1);
        Iterator<Row> rows = sheet.rowIterator();

        while (rows.hasNext()) {
            XSSFRow row = (XSSFRow) rows.next();

            // display row number in the console.
            System.out.println();

            // once get a row its time to iterate through cells.
            Iterator<Cell> cells = row.cellIterator();

            while (cells.hasNext()) {
                XSSFCell cell = (XSSFCell) cells.next();

                /*
                 * Now we will get the cell type and display the values
                 * accordingly.
                 */
                switch (cell.getCellType()) {
                case XSSFCell.CELL_TYPE_NUMERIC: {

                    // cell type numeric.
                    System.out.print(cell.getNumericCellValue() + "\t\t\t");

                    break;
                }

                case XSSFCell.CELL_TYPE_STRING: {

                    // cell type string.
                    XSSFRichTextString richTextString = cell
                            .getRichStringCellValue();

                    System.out.print(richTextString.getString() + "\t\t\t");

                    break;
                }

                default: {

                    // types other than String and Numeric.
                    System.out.println("Type not supported.");

                    break;
                }
                }
            }
        }

    }

    /**
     * The main executable method to test displayFromExcel method.
     * 
     * @param args
     */
    public static void main(String[] args) {
        xssff poiExample = new xssff();
        String xlsPath = "c://temp//data.xlsx";

        poiExample.displayFromExcel(xlsPath);
    }
}

Answer 1

好的，我找到了你的问题，你正在创建一本没有床单的新书

XSSFWorkbook workBook = new XSSFWorkbook();
XSSFSheet sheet = workBook.getSheetAt(1);  //error here, the workBook book has NO sheets!

您应该基于 InputStream 创建这本书

XSSFWorkbook workBook = WorkbookFactory.create(new PushbackInputStream(inputStream));
XSSFSheet sheet = workBook.getSheetAt(1);

或者更简单，只需传递文件名即可创建书：

XSSFWorkbook workBook = new XSSFWorkbook(xlsPath);
XSSFSheet sheet = workBook.getSheetAt(1);