yin*_*kou 1 cocoa-touch objective-c uitextfield uimenucontroller ios
我只想在文本字段变为活动状态后立即显示UIMenuController.
我现在正在做的是:
- (IBAction)textFieldeditingDidBegin:(UITextField *)sender {
// textfield menu item
UIMenuController *menu = [UIMenuController sharedMenuController];
[menu setTargetRect:sender.frame inView:self.view];
[menu setMenuVisible:YES animated:YES];
}
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该方法被调用,但它不会显示菜单...
如果我在文本字段上执行触摸+保持手势,它会定期出现.
我希望有一个简单的解决方案,谢谢
我找到了一个很好的解决方案.
UIMenuController使用此方法开始编辑文本字段时,可以轻松地显示:
- (void)textFieldDidBeginEditing:(UITextField *)textField
{
double delayInSeconds = 0.1;
dispatch_time_t popTime = dispatch_time(DISPATCH_TIME_NOW, delayInSeconds * NSEC_PER_SEC);
dispatch_after(popTime, dispatch_get_main_queue(), ^(void){
UIMenuController *menu = [UIMenuController sharedMenuController];
[menu setTargetRect:textField.frame inView:textField.superview];
[menu setMenuItems:[NSArray arrayWithObjects:
[[UIMenuItem alloc] initWithTitle:@"Test" action:@selector(test)],
nil]];
[menu setMenuVisible:YES animated:YES];
});
}
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我使用该dispatch_after调用确保在完成所有默认系统调用后显示菜单UITextField.
我还更改了方法的inView:self.view一部分,以确保菜单在文本字段的容器视图中正确显示.setTargetRect::inView:textField.superview
如果您还想禁用默认菜单控件,则UITextField可以将此方法添加到控制器:
- (BOOL)canPerformAction:(SEL)action withSender:(id)sender
{
if (action == @selector(cut:))
return NO;
else if (action == @selector(copy:))
return NO;
else if (action == @selector(paste:))
return NO;
else if (action == @selector(select:) || action == @selector(selectAll:))
return NO;
else
return [super canPerformAction:action withSender:sender];
}
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这项工作在模拟器中非常好.我希望这能帮到您!
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