pjm*_*m56 4 java oop generics design-patterns
重复使用前面的例子,想象一个动物园,动物园管理员必须"处理"新到达的动物(考虑将它们检入动物园).每只动物的登记过程取决于其类别分类(哺乳动物,鸟类等).
这些过程因分类学课程之间的根本差异而不同 - 例如,鸟类有翅膀,哺乳动物有牙齿.您可能还有一些过程的共享位对所有动物都适用,但我在这里省略了它们.
这是代码:
Animal.java
public interface Animal {
public AnimalProcessor<? extends Animal> getAnimalProcessor();
}
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Mammal.java
public abstract class Mammal implements Animal {
@Override
public AnimalProcessor<Mammal> getAnimalProcessor() {
return new MammalProcessor();
}
// Specific to mammals
public abstract int getToothCount();
}
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Bird.java
public abstract class Bird implements Animal {
@Override
public AnimalProcessor<Bird> getAnimalProcessor() {
return new BirdProcessor();
}
// Specific to birds
public abstract float getWingspan();
}
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AnimalProcessor.java
public interface AnimalProcessor<T extends Animal> {
public void process(T critter);
}
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MammalProcessor.java
public class MammalProcessor implements AnimalProcessor<Mammal> {
@Override
public void process(Mammal a) {
System.out.println("Tooth count is " + a.getToothCount());
}
}
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BirdProcessor.java
public class BirdProcessor implements AnimalProcessor<Bird> {
@Override
public void process(Bird a) {
System.out.print("Wingspan is " + a.getWingspan());
}
}
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Badger.java
public class Badger extends Mammal {
@Override
public int getToothCount() {
return 40;
}
}
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Condor.java
public class Condor extends Bird {
@Override
public float getWingspan() {
return 2.9f;
}
}
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ZooKeeper.java
import java.util.List;
public class ZooKeeper {
public void processNewAnimals(List<Animal> newcomers)
{
for(Animal critter : newcomers)
{
AnimalProcessor<? extends Animal> ap = critter.getAnimalProcessor();
// This line has a compilation error!
ap.process(critter);
}
}
}
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MainClass.java
import java.util.LinkedList;
import java.util.List;
public class MainClass {
public static void main(String[] args) {
ZooKeeper keeper = new ZooKeeper();
List<Animal> animals = new LinkedList<Animal>();
animals.add(new Badger());
animals.add(new Condor());
keeper.processNewAnimals(animals);
}
}
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在任何地方都没有警告,但ap.process(critter)无法编译.我知道这是因为AnimalProcessor<Bird>是没有的类型AnimalProcessor<Animal>,但我看不出如何解决这个问题.该调用<T extends Animal> getAnimalProcessor()将返回一个合适的AnimalProcessor<T extends Animal>,但我无法在代码中表达这一点.
也许我不应该首先将AnimalProcessor拉出来?
当然,目标是能够在Reptile不改变核心的情况下进行添加.
public interface Animal<THIS extends Animal<THIS>> {
AnimalProcessor<THIS> getAnimalProcessor();
}
public abstract class Mammal implements Animal<Mammal> {
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有点像Enum<E extends Enum<E>>.
删除该方法可能是一个更好的主意.