我正在尝试使用make编译我的代码.通常我编译我的代码如下:
mipsisa32r2el-timesys-linux-gnu-g++ -o testing -I/usr/include/libxml2 -L/develop/xc4/rootfs/parsecpp/lib -L/develop/xc4/rootfs/parsecpp/sqlite-mips2/lib -I/develop/xc4/rootfs/parsecpp/sqlite-mips2/include db.cpp main.cpp networkinterfacemodule.cpp network.cpp multiplex.cpp program.cpp service.cpp -lsqlite3 -lxml2
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为了摆脱这个长命令,我试着编写一个makefile:
CC= mipsisa32r2el-timesys-linux-gnu-g++
export LD_LIBRARY_PATH=:/parsecpp/sqlite-mips2/lib:/parsecpp/lib:/tmp/vixs_temp/DirectFB/single_core/lib
CFLAGS=-I/usr/include/libxml2 -I/develop/xc4/rootfs/parsecpp/sqlite-mips2/include
LDFLAGS=-L/develop/xc4/rootfs/parsecpp/lib -L/develop/xc4/rootfs/parsecpp/sqlite-mips2/lib
LIBS = -lsqlite3 -lxml2
PROG=testing
all: main.o db.o mod.o multiplex.o network.o networkinterfacemodule.o program.o service.o
$(CC) -o $(PROG) $(CFLAGS) $(LDFLAGS) main.o db.o mod.o multiplex.o network.o networkinterfacemodule.o program.o service.o $(LIBS)
main.o: main.cpp
$(CC) $(CFLAGS) $(LDFLAGS) main.cpp db.cpp networkinterfacemodule.cpp mod.cpp multiplex.cpp network.cpp program.cpp service.cpp $(LIBS)
db.o: db.cpp
$(CC) $(CFLAGS) $(LDFLAGS) db.cpp $(LIBS)
mod.o: mod.cpp
$(CC) $(CFLAGS) $(LDFLAGS) mod.cpp $(LIBS)
multiplex.o: multiplex.cpp
$(CC) $(CFLAGS) $(LDFLAGS) multiplex.cpp $(LIBS)
network.o: network.cpp
$(CC) $(CFLAGS) $(LDFLAGS) network.cpp $(LIBS)
networkmoduleinterface.o: networkinterfacemodule.cpp
$(CC) $(CFLAGS) $(LDFLAGS) networkinterfacemodule.cpp $(LIBS)
program.o: program.cpp
$(CC) $(CFLAGS) $(LDFLAGS) program.cpp $(LIBS)
service.o: service.cpp
$(CC) $(CFLAGS) $(LDFLAGS) service.cpp $(LIBS)
clean:
rm -rf *o testing
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然后我收到这个错误:
/opt/timesys/linux-gnu/toolchain/bin/../../toolchain/lib/crt1.o: In function `__start':
(.text+0xc): undefined reference to `main'
/opt/timesys/linux-gnu/toolchain/bin/../../toolchain/lib/crt1.o: In function `__start':
(.text+0x10): undefined reference to `main'
collect2: ld returned 1 exit status
make: *** [db.o] Error 1
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有谁能够帮我?
raj*_*uja 18
无论何时只是编译文件而不是链接它,都要使用"-c"标志.
例如 :-
db.o: db.cpp
$(CC) -c $(CFLAGS) $(LDFLAGS) db.cpp $(LIBS)
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此外,在编译时,不需要向编译器提供"$(LIBS)",只在链接时提供它们.您也不需要链接器标志,因为在使用"-c"标志时不会调用链接器.
所以你可以写,
db.o: db.cpp
$(CC) -c $(CFLAGS) db.cpp
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更新(根据评论): -
链接文件时,链接器需要一个且只有一个main函数.在上面的例子中,main函数没有定义db.cpp,因此虽然编译成功,但链接器会因为无法找到main函数而抛出错误.
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