rae*_*aeq 17 javascript ajax jquery response
所以我试图通过jQuery get从头响应中获取位置.我尝试使用getResponseHeader('Location')和getAllResponseHeaders(),但它们似乎都返回null.
这是我目前的代码
$(document).ready(function(){
var geturl;
geturl = $.ajax({
type: "GET",
url: 'http://searchlight.cluen.com/E5/Login.aspx?URLKey=uzr7ncj8)',
});
var locationResponse = geturl.getResponseHeader('Location');
console.log(locationResponse);
});
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Ber*_*rgi 33
异步请求返回时,标头将可用,因此您需要在成功回调中读取它们:
$.ajax({
type: "GET",
url: 'http://searchlight.cluen.com/E5/Login.aspx?URLKey=uzr7ncj8)',
success: function(data, status, xhr) {
console.log(xhr.getResponseHeader('Location'));
}
});
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小智 6
jQuery 将 XMLHttpRequest 对象抽象为一个所谓的“超级集”,它不公开 responseURL 字段。在他们的文档中,他们讨论了“jQuery XMLHttpRequest (jqXHR) 对象”
For backward compatibility with XMLHttpRequest, a jqXHR object will expose the following properties and methods:
readyState
responseXML and/or responseText when the underlying request responded with xml and/or text, respectively
status
statusText
abort( [ statusText ] )
getAllResponseHeaders() as a string
getResponseHeader( name )
overrideMimeType( mimeType )
setRequestHeader( name, value ) which departs from the standard by replacing the old value with the new one rather than concatenating the new value to the old one
statusCode( callbacksByStatusCode )
No onreadystatechange mechanism is provided, however, since done, fail, always, and statusCode cover all conceivable requirements.
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如您所见,无法获取响应 URL,因为 jqXHR API 没有公开它
对于jQuery Ajax中的一些头文件,您需要访问XMLHttpRequest对象
var xhr;
var _orgAjax = jQuery.ajaxSettings.xhr;
jQuery.ajaxSettings.xhr = function () {
xhr = _orgAjax();
return xhr;
};
$.ajax({
type: "GET",
url: 'http://example.com/redirect',
success: function(data) {
console.log(xhr.responseURL);
}
});
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或使用普通的JavaScript
var xhr = new XMLHttpRequest();
xhr.open('GET', "http://example.com/redirect", true);
xhr.onreadystatechange = function () {
if (this.readyState == 4 && this.status == 200) {
console.log(xhr.responseURL);
}
};
xhr.send();
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