如何在Android中获取联系人的电话号码

bri*_*ian 26 android cursor

我的代码如下:

String[] columns = {ContactsContract.Contacts._ID, ContactsContract.Contacts.DISPLAY_NAME, ContactsContract.Contacts.HAS_PHONE_NUMBER};
Cursor cursor = getContentResolver().query(ContactsContract.Contacts.CONTENT_URI, columns, null, null, null);

int ColumeIndex_ID = cursor.getColumnIndex(ContactsContract.Contacts._ID);
int ColumeIndex_DISPLAY_NAME = cursor.getColumnIndex(ContactsContract.Contacts.DISPLAY_NAME);
int ColumeIndex_HAS_PHONE_NUMBER = cursor.getColumnIndex(ContactsContract.Contacts.HAS_PHONE_NUMBER);

while(cursor.moveToNext()) 
{   
    String id = cursor.getString(ColumeIndex_ID);
    String name = cursor.getString(ColumeIndex_DISPLAY_NAME);
    String has_phone = cursor.getString(ColumeIndex_HAS_PHONE_NUMBER);

    if(!has_phone.endsWith("0")) 
    {
        System.out.println(name);
        GetPhoneNumber(id);
    }           
}

cursor.close();


public String GetPhoneNumber(String id) 
{
    String number = "";
    Cursor phones = getContentResolver().query(ContactsContract.CommonDataKinds.Phone.CONTENT_URI, null, ContactsContract.CommonDataKinds.Phone._ID + " = " + id, null, null);

    if(phones.getCount() > 0) 
    {
        while(phones.moveToNext()) 
        {
            number = phones.getString(phones.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER));
        }
        System.out.println(number);
    }

    phones.close();

    return number;
}
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我的联系人姓名成功,但电话号码失败了GetPhoneNumber().始终等于0. 我
该如何修改? phones.getCount()

K_A*_*nas 66

Android Contact API For 2.0

//
//  Find contact based on name.
//
ContentResolver cr = getContentResolver();
Cursor cursor = cr.query(ContactsContract.Contacts.CONTENT_URI, null,
    "DISPLAY_NAME = '" + NAME + "'", null, null);
if (cursor.moveToFirst()) {
    String contactId =
        cursor.getString(cursor.getColumnIndex(ContactsContract.Contacts._ID));
    //
    //  Get all phone numbers.
    //
    Cursor phones = cr.query(Phone.CONTENT_URI, null,
        Phone.CONTACT_ID + " = " + contactId, null, null);
    while (phones.moveToNext()) {
        String number = phones.getString(phones.getColumnIndex(Phone.NUMBER));
        int type = phones.getInt(phones.getColumnIndex(Phone.TYPE));
        switch (type) {
            case Phone.TYPE_HOME:
                // do something with the Home number here...
                break;
            case Phone.TYPE_MOBILE:
                // do something with the Mobile number here...
                break;
            case Phone.TYPE_WORK:
                // do something with the Work number here...
                break;
        }
    }
    phones.close();
}
cursor.close();
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有关更多信息,请参阅此链接

  • Cursor cursor = cr.query(ContactsContract.Contacts.CONTENT_URI, null, "DISPLAY_NAME = '" + NAME + "'", null, null); 我怎么得到它 (2认同)

kal*_*dar 7

试试这个.

    ContentResolver cr = getContentResolver();
    Cursor cur = cr.query(ContactsContract.Contacts.CONTENT_URI, null,
            null, null, null);
    if (cur.getCount() > 0) {
        while (cur.moveToNext()) {
            String id = cur.getString(cur.getColumnIndex(ContactsContract.Contacts._ID));
            String name = cur.getString(cur.getColumnIndex(ContactsContract.Contacts.DISPLAY_NAME));
            Log.i("Names", name);
            if (Integer.parseInt(cur.getString(cur.getColumnIndex(ContactsContract.Contacts.HAS_PHONE_NUMBER))) > 0) 
            {
                // Query phone here. Covered next
                Cursor phones = getContentResolver().query(ContactsContract.CommonDataKinds.Phone.CONTENT_URI,null,ContactsContract.CommonDataKinds.Phone.CONTACT_ID +" = "+ id,null, null); 
                while (phones.moveToNext()) { 
                         String phoneNumber = phones.getString(phones.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER));
                         Log.i("Number", phoneNumber);
                        } 
                phones.close(); 
            }

        }
    }
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  • 对于大约500个接触,这个持续30秒; 不像K_Anas的答案,持续约半秒.我不建议使用这个.至少它不适合我 (5认同)