将多个文件读入多个数据帧

Question

在d:\文件夹中,我有很多Stata文件,例如data_aa_1.dta,data_aa_2.dta,data_aa_3.dta data_bb_1.dta,data_bb_2.dta,data_bb_3.dta,data_cc_1.dta ....我想转换这些文件获得与R中的dta文件一样多的数据帧.所以,我相信我必须循环c("aa","bb","cc")和c(1:3).我尝试过以下内容:

library(foreign)

for(i in c("aa","bb","cc"){
    for (j in 1:3){
        data_[i]_[j] <-read.dta("d:/folder/data_[i]_[j].dta")
    }
}

但是,这看起来不对 - 当然.

任何帮助将不胜感激.

谢谢!

Answer 1

试试这个,

fl = list.files(pattern = "dta", path = "d:/folder", 
                full.names = TRUE)
dl = lapply(fl, foreign::read.dta)
names(dl) = tools::file_path_sans_ext(fl)
str(dl)

Answer 2

然而,毫无疑问,这是一个更优雅的解决方案

library(foreign)



for(i in c("aa","bb","cc"){
    for (j in 1:3){
      obj_name <- paste('data', i, j, sep ='_')
      file_name <- file.path('d:/folder',paste(obj_name,'dta', sep ='.'))
      input <- read.dta(file_name)
      assign(obj_name, value = input)

    }
}

编辑

避免for循环,并使用@joran的建议list.files

dta_files <- list.files('d:/folder', pattern = '.dta', full.names = T)

lapply(dta_files, function(fname){
  input <- read.dta(fname) 
  obj_name <- tools::file_path_sans_ext(basename(fname))
  assign(obj_name, value input, env = .GlobalEnv)})