SQL Stairstep查询

Nat*_*han 16 sql sql-server sql-server-2012

我需要一些帮助来生成一个MS SQL 2012查询,该查询将匹配所需的阶梯输出.行按一个日期范围(帐户提交日期月份)汇总数据,列按另一个日期范围(付款日期月份)汇总

表1:帐户跟踪为集合放置的帐户.

CREATE TABLE [dbo].[Accounts](
    [AccountID] [nchar](10) NOT NULL,
    [SubmissionDate] [date] NOT NULL,
    [Amount] [money] NOT NULL,
CONSTRAINT [PK_Accounts] PRIMARY KEY CLUSTERED (AccountID ASC))

INSERT INTO [dbo].[Accounts] VALUES ('1000', '2012-01-01', 1999.00)
INSERT INTO [dbo].[Accounts] VALUES ('1001', '2012-01-02', 100.00)
INSERT INTO [dbo].[Accounts] VALUES ('1002', '2012-02-05', 350.00)
INSERT INTO [dbo].[Accounts] VALUES ('1003', '2012-03-01', 625.00)
INSERT INTO [dbo].[Accounts] VALUES ('1004', '2012-03-10', 50.00)
INSERT INTO [dbo].[Accounts] VALUES ('1005', '2012-03-10', 10.00)
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表2:Trans跟踪付款

CREATE TABLE [dbo].[Trans](
    [TranID] [int] IDENTITY(1,1) NOT NULL,
    [AccountID] [nchar](10) NOT NULL,
    [TranDate] [date] NOT NULL,
    [TranAmount] [money] NOT NULL,
CONSTRAINT [PK_Trans] PRIMARY KEY CLUSTERED (TranID ASC))

INSERT INTO [dbo].[Trans] VALUES (1000, '2012-01-15', 300.00)
INSERT INTO [dbo].[Trans] VALUES (1000, '2012-02-15', 300.00)
INSERT INTO [dbo].[Trans] VALUES (1000, '2012-03-15', 300.00)
INSERT INTO [dbo].[Trans] VALUES (1002, '2012-02-20', 325.00)
INSERT INTO [dbo].[Trans] VALUES (1002, '2012-04-20', 25.00)
INSERT INTO [dbo].[Trans] VALUES (1003, '2012-03-24', 625.00)
INSERT INTO [dbo].[Trans] VALUES (1004, '2012-03-28', 31.00)
INSERT INTO [dbo].[Trans] VALUES (1004, '2012-04-12', 5.00)
INSERT INTO [dbo].[Trans] VALUES (1005, '2012-04-08', 7.00)
INSERT INTO [dbo].[Trans] VALUES (1005, '2012-04-28', 3.00)
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这是所需的输出应该是什么样子

                                 *Total Payments in Each Month*
SubmissionYearMonth TotalAmount | 2012-01  2012-02  2012-03  2012-04 
--------------------------------------------------------------------
2012-01             2099.00     |  300.00   300.00   300.00     0.00
2012-02             350.00      |           325.00     0.00    25.00
2012-03             685.00      |                    656.00    15.00
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前两列按月分组Account.Amount分组.

对于放置在当前行的给定月份中的帐户,最后4列按月累计Tran.TranAmount.

我一直在使用的查询感觉很接近.我只是没有正确的滞后.这是我到目前为止所使用的查询:

Select SubmissionYearMonth, 
       TotalAmount,
       pt.[0] AS MonthOld0,
       pt.[1] AS MonthOld1,
       pt.[2] AS MonthOld2,
       pt.[3] AS MonthOld3,
       pt.[4] AS MonthOld4,
       pt.[5] AS MonthOld5,
       pt.[6] AS MonthOld6,
       pt.[7] AS MonthOld7,
       pt.[8] AS MonthOld8,
       pt.[9] AS MonthOld9,
       pt.[10] AS MonthOld10,
       pt.[11] AS MonthOld11,
       pt.[12] AS MonthOld12,
       pt.[13] AS MonthOld13

From (
       SELECT Convert(Char(4),Year(SubmissionDate)) + '-' + Right('00' + Convert(VarChar(2), DatePart(Month, SubmissionDate)),2) AS SubmissionYearMonth, 
       SUM(Amount) AS TotalAmount
       FROM   Accounts
       GROUP BY Convert(Char(4),Year(SubmissionDate)) + '-' + Right('00' + Convert(VarChar(2), DatePart(Month, SubmissionDate)),2)
     ) 
AS AccountSummary
OUTER APPLY
(
SELECT *
FROM (
       SELECT CASE WHEN DATEDIFF(Month, SubmissionDate, TranDate) < 13
                   THEN DATEDIFF(Month, SubmissionDate, TranDate)
                   ELSE 13
              END AS PaymentMonthAge,
              TranAmount
       FROM Trans INNER JOIN Accounts ON Trans.AccountID = Accounts.AccountID
       Where Convert(Char(4),Year(TranDate)) + '-' + Right('00' + Convert(VarChar(2), DatePart(Month, TranDate)),2)
             = AccountSummary.SubmissionYearMonth
       ) as TransTemp
       PIVOT (SUM(TranAmount)
              FOR PaymentMonthAge IN ([0],
                                      [1],
                                      [2],
                                      [3],
                                      [4],
                                      [5],
                                      [6],
                                      [7],
                                      [8],
                                      [9],
                                      [10],
                                      [11],
                                      [12],
                                      [13])) as TransPivot
) as pt
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它产生以下输出:

SubmissionYearMonth TotalAmount MonthOld0 MonthOld1 MonthOld2 MonthOld3 ...
2012-01             2099.00     300.00    NULL      NULL      NULL      ...
2012-02             350.00      325.00    300.00    NULL      NULL      ...
2012-03             685.00      656.00    NULL      300.00    NULL      ...
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至于列日期标题.我不确定这里最好的选择是什么.我可以添加一组额外的列并创建一个我可以在结果报告中使用的计算值.

SQL小提琴:http://www.sqlfiddle.com/#!6 / 272e5/1 /0

Tho*_*mas 5

由于您使用的是SQL Server 2012,因此我们可以使用Format函数使日期非常漂亮.没有必要按字符串分组.相反,我发现尽可能长时间使用正确的数据类型并且仅在显示器上使用Format或Convert(或者根本不使用中间层处理显示器)是有用的.

在这个解决方案中,我任意假设最早的TransDate并从那个月的第一天中提取.但是,可以使用所需开始日期的静态值轻松替换该表达式,此解决方案将采用该表达式和接下来的12个月.

With SubmissionMonths As
  (
  Select DateAdd(d, -Day(A.SubmissionDate) + 1, A.SubmissionDate) As SubmissionMonth
    , A.Amount
  From dbo.Accounts As A
  )
  , TranMonths As
  (
  Select DateAdd(d, -Day(Min( T.TranDate )) + 1, Min( T.TranDate )) As TranMonth
      , 1 As MonthNum
  From dbo.Accounts As A
    Join dbo.Trans As T
      On T.AccountId = A.AccountId
    Join SubmissionMonths As M
      On A.SubmissionDate >= M.SubmissionMonth
        And A.SubmissionDate < DateAdd(m,1,SubmissionMonth)
  Union All
  Select DateAdd(m, 1, TranMonth), MonthNum + 1
  From TranMonths
  Where MonthNum < 12
  )
  , TotalBySubmissionMonth As
  (
  Select M.SubmissionMonth, Sum( M.Amount ) As Total
  From SubmissionMonths As M
  Group By M.SubmissionMonth
  )
Select Format(SMT.SubmissionMonth,'yyyy-MM') As SubmissionMonth, SMT.Total
  , Sum( Case When TM.MonthNum = 1 Then T.TranAmount End ) As Month1
  , Sum( Case When TM.MonthNum = 2 Then T.TranAmount End ) As Month2
  , Sum( Case When TM.MonthNum = 3 Then T.TranAmount End ) As Month3
  , Sum( Case When TM.MonthNum = 4 Then T.TranAmount End ) As Month4
  , Sum( Case When TM.MonthNum = 5 Then T.TranAmount End ) As Month5
  , Sum( Case When TM.MonthNum = 6 Then T.TranAmount End ) As Month6
  , Sum( Case When TM.MonthNum = 7 Then T.TranAmount End ) As Month7
  , Sum( Case When TM.MonthNum = 8 Then T.TranAmount End ) As Month8
  , Sum( Case When TM.MonthNum = 9 Then T.TranAmount End ) As Month9
  , Sum( Case When TM.MonthNum = 10 Then T.TranAmount End ) As Month10
  , Sum( Case When TM.MonthNum = 11 Then T.TranAmount End ) As Month11
  , Sum( Case When TM.MonthNum = 12 Then T.TranAmount End ) As Month12
From TotalBySubmissionMonth As SMT
  Join dbo.Accounts As A
    On A.SubmissionDate >= SMT.SubmissionMonth
      And A.SubmissionDate < DateAdd(m,1,SMT.SubmissionMonth)
  Join dbo.Trans As T
    On T.AccountId = A.AccountId
  Join TranMonths As TM
    On T.TranDate >= TM.TranMonth
      And T.TranDate < DateAdd(m,1,TM.TranMonth)
Group By SMT.SubmissionMonth, SMT.Total
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SQL小提琴版


Nat*_*han 1

托马斯,我用你的回复作为我最终使用的以下解决方案的灵感。

我首先创建一个 SubmissionDate、TranDate 交叉连接骨架日期矩阵,稍后使用它来连接 AccountSummary 和 TranSummary 数据。

生成的查询输出未按照每个 TranDate 月份的列进行格式化。相反,我使用 SQL Server Reporting Services 矩阵中的输出,并使用基于 TranSummaryMonthNum 列的列分组来获取所需的格式化输出。

SQL 小提琴版本

;
WITH 
    --Generate a list of Dates, from the first SubmissionDate, through today.
    --Note: Requires the use of: 'OPTION (MAXRECURSION 0)' to generate a list with more than 100 dates.
    CTE_AutoDates AS
    ( Select Min(SubmissionDate) as FiscalDate
      From Accounts
      UNION ALL
      SELECT DATEADD(Day, 1, FiscalDate)
      FROM CTE_AutoDates
      WHERE DATEADD(Day, 1, FiscalDate) <= GetDate()
    ),

    FiscalDates As
    ( SELECT FiscalDate,
             DATEFROMPARTS(Year(FiscalDate), Month(FiscalDate), 1) as FiscalMonthStartDate  
      FROM CTE_AutoDates
      --Optionaly filter Fiscal Dates by the last known Math.Max(SubmissionDate, TranDate)
      Where FiscalDate <= (Select Max(MaxDate)
                           From (Select Max(SubmissionDate) as MaxDate From Accounts
                                 Union All 
                                 Select Max(TranDate) as MaxDate From Trans
                                ) as MaxDates
                         )
    ),

    FiscalMonths as
    ( SELECT Distinct FiscalMonthStartDate 
      FROM FiscalDates
    ),

    --Matrix to store the reporting date groupings for the Account submission and payment periods.
    SubmissionAndTranMonths AS
    ( Select AM.FiscalMonthStartDate as SubmissionMonthStartDate,
             TM.FiscalMonthStartDate as TransMonthStartDate,
             DateDiff(Month, (Select Min(FiscalMonthStartDate) From FiscalMonths), TM.FiscalMonthStartDate) as TranSummaryMonthNum
      From   FiscalMonths AS AM
             Join FiscalMonths AS TM
             ON TM.FiscalMonthStartDate >= AM.FiscalMonthStartDate
    ),

    AccountData as
    ( Select A.AccountID, 
             A.Amount,
             FD.FiscalMonthStartDate as SubmissionMonthStartDate
      From   Accounts as A
           Inner Join FiscalDates as FD
             ON A.SubmissionDate = FD.FiscalDate
    ),


    TranData as
    ( Select T.AccountID,
             T.TranAmount,
             AD.SubmissionMonthStartDate,
             FD.FiscalMonthStartDate as TranMonthStartDate
      From   Trans as T
           Inner Join AccountData as AD
             ON T.AccountID = AD.AccountID
           Inner Join FiscalDates AS FD
             ON T.TranDate = FD.FiscalDate
    ),

    AccountSummaryByMonth As
    ( Select ASM.FiscalMonthStartDate,
             Sum(AD.Amount) as TotalSubmissionAmount
      From   FiscalMonths as ASM
           Inner Join AccountData as AD
             ON ASM.FiscalMonthStartDate = AD.SubmissionMonthStartDate
      Group By
             ASM.FiscalMonthStartDate
    ),

    TranSummaryByMonth As
    ( Select STM.SubmissionMonthStartDate,
             STM.TransMonthStartDate,
             STM.TranSummaryMonthNum,
             Sum(TD.TranAmount) as TotalTranAmount
      From   SubmissionAndTranMonths as STM
           Inner Join TranData as TD
             ON STM.SubmissionMonthStartDate = TD.SubmissionMonthStartDate
                AND STM.TransMonthStartDate = TD.TranMonthStartDate
      Group By
             STM.SubmissionMonthStartDate,
             STM.TransMonthStartDate,
             STM.TranSummaryMonthNum
    )

--#Inspect 1
--Select * From SubmissionAndTranMonths
--OPTION (MAXRECURSION 0)

--#Inspect 1 Results
--SubmissionMonthStartDate TransMonthStartDate TranSummaryMonthNum
--2012-01-01               2012-01-01          0
--2012-01-01               2012-02-01          1
--2012-01-01               2012-03-01          2
--2012-01-01               2012-04-01          3
--2012-02-01               2012-02-01          1
--2012-02-01               2012-03-01          2
--2012-02-01               2012-04-01          3
--2012-03-01               2012-03-01          2
--2012-03-01               2012-04-01          3
--2012-04-01               2012-04-01          3

--#Inspect 2
--Select * From AccountSummaryByMonth
--OPTION (MAXRECURSION 0)

--#Inspect 2 Results
--FiscalMonthStartDate TotalSubmissionAmount
--2012-01-01           2099.00
--2012-02-01           350.00
--2012-03-01           685.00

--#Inspect 3
--Select * From TranSummaryByMonth
--OPTION (MAXRECURSION 0)

--#Inspect 3 Results
--SubmissionMonthStartDate TransMonthStartDate TranSummaryMonthNum TotalTranAmount
--2012-01-01               2012-01-01          0                   300.00
--2012-01-01               2012-02-01          1                   300.00
--2012-01-01               2012-03-01          2                   300.00
--2012-02-01               2012-02-01          1                   325.00
--2012-02-01               2012-04-01          3                   25.00
--2012-03-01               2012-03-01          2                   656.00
--2012-03-01               2012-04-01          3                   15.00

Select STM.SubmissionMonthStartDate,
       ASM.TotalSubmissionAmount,
       STM.TransMonthStartDate,
       STM.TranSummaryMonthNum,
       TSM.TotalTranAmount
From   SubmissionAndTranMonths as STM
     Inner Join AccountSummaryByMonth as ASM
       ON STM.SubmissionMonthStartDate = ASM.FiscalMonthStartDate
     Left Join TranSummaryByMonth AS TSM
       ON STM.SubmissionMonthStartDate = TSM.SubmissionMonthStartDate
          AND STM.TransMonthStartDate = TSM.TransMonthStartDate
Order By STM.SubmissionMonthStartDate, STM.TranSummaryMonthNum
OPTION (MAXRECURSION 0)

--#Results
--SubmissionMonthStartDate TotalSubmissionAmount TransMonthStartDate TranSummaryMonthNum TotalTranAmount
--2012-01-01               2099.00               2012-01-01           0                  300.00
--2012-01-01               2099.00               2012-02-01           1                  300.00
--2012-01-01               2099.00               2012-03-01           2                  300.00
--2012-01-01               2099.00               2012-04-01           3                  NULL
--2012-02-01               350.00                2012-02-01           1                  325.00
--2012-02-01               350.00                2012-03-01           2                  NULL
--2012-02-01               350.00                2012-04-01           3                  25.00
--2012-03-01               685.00                2012-03-01           2                  656.00
--2012-03-01               685.00                2012-04-01           3                  15.00
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  • 亲爱的内森,如果有人对您的查询有很大帮助,那么我认为您应该选择那个人的答案,而不是提供您自己的答案并选择它。 (3认同)